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neonofarm [45]
3 years ago
7

There are three types of rocks on Earth. Each rock type forms in a different way. Igneous rocks were the first rocks on Earth. T

hey form from molten rock. Molten rock is rock that has turned to liquid because of extreme heat. Lava is the name for the molten rock that erupts from volcanoes. When molten rock is below the Earth’s surface, it’s called magma. When molten rock—either lava or magma—cools, it hardens into a solid. This forms igneous rocks. Some examples of igneous rocks are granite, obsidian and basalt. Much of Hawaii’s coast is covered in basalt. Waves break the basalt down over time, creating the black sand of some Hawaiian beaches.
Which of the following is true about lava and magma?
A. Lava and magma are both types of molten rock.
B. Magma uses waves to break down lava over time.
C. When magma cools and hardens it becomes lava.
D. Magma is called lava when it’s below the Earth’s surface.
Physics
2 answers:
MrMuchimi3 years ago
7 0

Answer:

Answer is 1, both are molten rocks.

zubka84 [21]3 years ago
5 0

Answer:

A

Explanation:

hot rocks bois, gottem

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m_1 v_1 r_1 = m_2 v_2 r_2 

Assuming that the mass did not change, conservation of angular momentum demands that 

v_1 r_1 = v_2 r_2 

or 

v1 = v_2 (r_2/r_1) 

Setting r_1 = 40,000 AU and v_2 = 5 km/s and r_2 = 39 AU (appropriate for Pluto's orbit) we have 

v_2 = 5 km/s (39 AU /40,000 AU) = 4.875E-3 km/s

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3 0
3 years ago
The critical angle for a certain air-liquid surface is 47.7°. What is the index of refraction of the liquid? Round to the neares
KengaRu [80]

Answer:

The index of refraction of the liquid is 1.35.

Explanation:

It is given that,

Critical angle for a certain air-liquid surface, \theta_1=47.7^{\circ}

Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1

Using Snell's law for air liquid interface as :

n_1\ sin\theta_1=n_2\ sin(90)

n_1\ sin(47.7)=1

n_1=\dfrac{1}{sin(47.7)}

n_1=1.35

So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.

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The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 7.00 s, at which time it
Keith_Richards [23]

Answer:

The no. of revolutions does the tub turn while it is in motion is = 52.51 revolutions

Explanation:

Given data

\omega_1 = 0

\omega_2 = 5 \frac{rev}{sec}

Time taken = 7 sec

(1). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha  = \frac{5}{7}

\alpha  = 0.714 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_1

5^{2} = 0 + 2 (0.714) \theta_1

\theta_1 = 17.5 \ rev  -------- (1)

(2). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha = - \frac{5}{14}

\alpha = - 0.357 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_2

0^{2} = 5^{2} + 2 (-0.357) \theta_2

\theta_2 = 35.01 rev  -------  (2)

Total no of revolution made by the machine is

\theta = \theta_1 + \theta_2

\theta = 17.5 + 35.01

\theta = 52.51 rev

Therefore the no. of revolutions does the tub turn while it is in motion is = 52.51  rev

8 0
3 years ago
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