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Jlenok [28]
3 years ago
8

Warning triangles, flares, a vehicle's hazard lights, or emergency vehicles ahead, are all clues that you might be approaching _

_____________________.
a,A funeral procession
b.A collision scene
c.A railroad crossing
d.A parade ceremony
Physics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

B. A collision scene

Explanation:

It could have been a parade ceremony, but, if you notice the vehicle's hazard lights or an emergency vehicle ahead, it is common sense to figure that they is a collision scene nearby.

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Explain briefly where the energy come from when a liquid Rises against Gravity in a capillary tube​
SSSSS [86.1K]

Answer:

Surface tension

Explanation:

When liquid rises against gravity in a capillary tube, the energy comes from surface tension.

This is because surface tension is the energy that's needed to increase the liquid surface area.

As a result of hydrogen bonding present in Water, it usually has high surface tension which makes it to possess a tough skin that can make it not to break despite high forces applied to it.

The liquid will be in contact with the capillary tube and as such experiences surface tension which in turn makes the capillary tube to experience an upward force that makes the liquid begin to rise up.

The more the liquid keeps rising, the more it gets to the point where the surface tension becomes balanced from the weight of the liquid.

3 0
3 years ago
A hot-air balloon is descending at a rate of 2.1 m/s when a passenger drops a camera. If the camera is 42 m above the ground whe
zysi [14]

Answer:

a) 2.7s

b) 29 m/s

Explanation:

The equation for the velocity  and position of a free fall are the following

v=v_{0}-gt -(1)

x=x_{0}+v_{0}t-gt^{2}/2 - (2)

Since the hot-air ballon is <em>descending </em>at 2.1m/s and the camera is dropped at 42 m above the ground:

v_{0}=-2.1m/s

x_{0}=42m

To calculate the time which it takes to reach the ground we use eq(2) with x=0, and look for the positive solution of t:

t = \frac{1}{84}(2.1\pm\sqrt{2.1^{2} - 4\times42\times9.81/2} )

        t = 2.71996

Rounding to two significant figures:

       t = 2.7 s

Now we calculate the velocity the camera had just before it lands using eq(1) with t=2.7s

v=-2.1-9.81*(2.71996)

      v = -28.782 m/s

Rounding to two significant figures:

      v = -29 m/s

where the minus sign indicates the downwards direction

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4 years ago
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After exercise, your heart rate is ____ and you need to slowly bring it back to normal
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The answer is <em>C.) Elevated</em>

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