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4 years ago

Can someone please help me with this

Mathematics

1 answer:

amm18124 years ago

6 0

Answer:

Then the best way to phrase it would be to jump right into the question without I need your help, because saying so makes it sound as though you have more of an urgent, sensitive, personal problem than a simple question or two (they might be a bit taken aback by the phrase).

However, if you have several questions (let's say more than 2), or if you just want to sound a bit more polite, you could preface the content with a phrase like I was wondering I you might be able to answer a few questions of mine, or, I have a few questions that I was hoping you might be able to help me with.

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What is the base in the following: -55 power to 4

Alik [6]

Answer:

-55

Step-by-step explanation:

It would be -55 because the exponent is 4. So, that would leave -55 to be the right answer.

7 0

3 years ago

Wath is the fraction 4over10 plus 3over5

Over [174]

The answer is a whole number, and it happens to be 1

7 0

4 years ago

Read 2 more answers

A.)4<br> B.)10<br> C.)18<br> Which one could be the answer I’m lost.

kirill115 [55]

f(x) = ((x^2) / 3) + x, for f(6)

f(6) = ((6^2) / 3) + 6

Square 6

f(6) = (36 / 3) + 6

Divide 36 by 3

f(6) = 12 + 6

Combine like terms

f(6) = 18

4 0

3 years ago

What is 1/5 into a decimal?

andrey2020 [161]

Answer:

0.2

Step-by-step explanation:

it just is. look it up they will have an explanation

6 0

3 years ago

Can you tell me how to calculate R for below Matrix ?

scoray [572]

Answer:

The rank of the matrix is 3.

Step-by-step explanation:

Consider the prided information.

$x=\begin{bmatrix}x_1\\ x_2\\ x_3\end{bmatrix}=\begin{bmatrix}9&2&6&5&8\\ 12&8&6&4&10\\ 3&4&0&2&1\end{bmatrix}$

Reduce the matrix in row echelon form as shown:

$R_1\:\leftrightarrow \:R_2\begin{bmatrix}12&8&6&4&10\\ 9&2&6&5&8\\ 3&4&0&2&1\end{bmatrix}\\$

$R_2\:\leftarrow \:R_2-\frac{3}{4}\cdot \:R_1\ and\ R_3\:\leftarrow \:R_3-\frac{1}{4}\cdot \:R_1\\\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&2&-\frac{3}{2}&1&-\frac{3}{2}\end{bmatrix}$

$R_3\:\leftarrow \:R_3+\frac{1}{2}\cdot \:R_2\\\begin{bmatrix}12&8&6&4&10\\ 0&-4&\frac{3}{2}&2&\frac{1}{2}\\ 0&0&-\frac{3}{4}&2&-\frac{5}{4}\end{bmatrix}$

$R_2\:\leftarrow \:R_2-\frac{3}{2}\cdot \:R_3\ and\ R_1\:\leftarrow \:R_1-6\cdot \:R_3\\\begin{bmatrix}12&8&0&20&0\\ 0&-4&0&6&-2\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}\\R_2\:\leftarrow \:-\frac{1}{4}\cdot \:R_2\ , \ R_1\:\leftarrow \:R_1-8\cdot \:R_2\ and\ \:R_1\:\leftarrow \frac{1}{12}\cdot \:R_1\\\begin{bmatrix}1&0&0&\frac{8}{3}&-\frac{1}{3}\\ 0&1&0&-\frac{3}{2}&\frac{1}{2}\\ 0&0&1&-\frac{8}{3}&\frac{5}{3}\end{bmatrix}$

The rank of a matrix is the number of non zeros rows.

Thus, the rank of the matrix is 3.

6 0

3 years ago