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3 years ago

6

Can someone please help me with this

1 answer:

amm18123 years ago

6 0

Answer:

Then the best way to phrase it would be to jump right into the question without I need your help, because saying so makes it sound as though you have more of an urgent, sensitive, personal problem than a simple question or two (they might be a bit taken aback by the phrase).

However, if you have several questions (let's say more than 2), or if you just want to sound a bit more polite, you could preface the content with a phrase like I was wondering I you might be able to answer a few questions of mine, or, I have a few questions that I was hoping you might be able to help me with.

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6.24 x 10-5 - 4.091 x 103 =

castortr0y [4]

Is the 10 taking away 5 or was it meant to me 10.5 ?

6 0

2 years ago

Read 2 more answers

Please I neeed help

Novosadov [1.4K]

The answer is 59049 hope this helps

8 0

2 years ago

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Marge cuts 16 pieces of tape. each piece is 3/8 inches long. how much tape did she use

hoa [83]

16 x 3/8 so 16/1 x 3/8 = 48/8. 48 divided by 8 is 6. So 6 inches.

3 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago

Someone help plz plz plz

prisoha [69]

Answer:I think it's 3 7.75/20 hours

Step-by-step explanation:

Multiply 2/15 by 20 (2x20 and 15x20)

Then 13/20 by 15 (13x15 and 20x15)

Subtract (195/300 - 40/300)

And you get 155/300

Then divide by 20 because dividing by 15 gives you 10.333333

So divide 155/300 by 20 (155÷20 and 300÷20)

And you get 7.75/20

Finally subtract the 2 hours from 5 hours and get 3 hours

Your answer is 3 7.75 hours

5 0

2 years ago