The Ksp of the solution is 1.97 * 10^-9.
<h3>What is the pH?</h3>
The pH is defined as the hydrogen ion concentration of the solution. Now we have the pH of the solution as 10.9.
We know that;
pOH = 14 - pH
pOH = 14 - 10.9
pOH = 3.1
[OH^-] = Antilog [-3.1]
[OH^-] =7.9 * 10^-4 M
Now
Ksp = [M^2+] [2OH^-]^2
Ksp = s * (2s)^2
Ksp = 4s^3
Now s = 7.9 * 10^-4 M
Ksp = 4(7.9 * 10^-4)^3
Ksp = 1.97 * 10^-9
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ZnS(s) + 2O₂(g) ⇒ZnSO₄(s)
<h3>Further explanation</h3>
The oxidation-reduction reaction or abbreviated as Redox is a chemical reaction in which there is a change in oxidation number
Oxidation is an increase in oxidation number, while reduction is a decrease in oxidation number.
Reaction
ZnS(s) + 2O₂(g) ⇒ZnSO₄(s)
S²⁻ (-2 in ZnS) to S⁺⁶(+6 in ZnSO₄) ⇒ oxidation
O₂(0 in O₂) to O⁻²(-2 in ZnSO₄)⇒ reduction
<h3>
<u>Answer</u></h3>
4. loses 2 electrons
<h3>
<u>EXPLANATION</u></h3>
Mg²+ has 10 electrons while Mg has 12 electrons.
Solution:
The molecular equation is:
Now, the oxide ion reacts with water to produce hydroxide ions,
The ionic equation is:
The 
ions are present on both the sides, so the net ionic equation becomes,
Now, to determine acid and base, we will look at the definitions
Acid: It is defined as proton donor that is it donates 
ions.
Base: It is defined as proton acceptor that is it accepts ions.
In the ionic equation, water is donating ions to 
therefore it acts as an acid and oxide ion acts as a base.
