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Andre45 [30]
3 years ago
6

A solid cylinder has a diameter of 17.4 mm and a length of 50.3mm. It's mass is 49g . What is its density of the cylinder in met

ric tonnes per cubic metre? Give your answer to 1 significant figure.​
Physics
1 answer:
Tamiku [17]3 years ago
6 0

Answer:

4 tonne/m³

Explanation:

ρ = m / V

ρ = 49 g / (π (17.4 mm / 2)² (50.3 mm))

ρ = 0.0041 g/mm³

Converting to tonnes/m³:

ρ = 0.0041 g/mm³ (1 kg / 1000 g) (1 tonne / 1000 kg) (1000 mm / m)³

ρ = 4.1 tonne/m³

Rounding to one significant figure, the density is 4 tonne/m³.

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Impulse: A batter applies an average force of 8000 N to a baseball for 1.1 ms. What is the magnitude of the impulse delivered to
fiasKO [112]

The magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

<h3>Impulse experienced by objects</h3>

The impulse experienced by any object is equal to the change in the momentum of the object.

The magnitude of the impulse delivered to the baseball by the bat is calculated by applying the following equation.

J = Ft

where;

  • F is applied force = 8000 N
  • t is time, = 1.1 ms

J = (8000) x (1.1 x 10⁻³)

J = 8.8 Ns

Thus, the magnitude of the impulse delivered to the baseball by the bat is 8.8 Ns.

Learn more about impulse here: brainly.com/question/229647

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3 years ago
The visible spectrum refers to the tiny portion of the electromagnetic spectrum that we ________.
marusya05 [52]

Answer:

are able to see/observe

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Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, wh
mel-nik [20]

Answer:u=\frac{v}{2}\sqrt{5-4sin\phi }

Explanation:

Given

Both cars mass is m

and solving problem in Vertical and horizontal direction

considering + y and +x to be positive and u be the final velocity of system

Conserving Momentum in Vertical direction

m(2v)+m(-vsin\phi )=2m(ucos\theta )

2ucos\theta =v(2-sin\theta )------1

Conserving momentum in x direction

mvcos\phi =2musin\theta-----2

squaring and adding 1 &2

(2u)^2=(2v-vsin\phi )^2+(vcos\phi )^2

4u^2=4v^2+v^2-4v^2sin\phi

4u^2=5v^2-4v^2sin\phi

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