Question

Microwave ovens emit microwave energy with a wavelength of 12.4 cm. what is the energy of exactly one photon of this microwave radiation?

Answer 1

Formula- E = hc/ {wavelength} Given in quation-wavelength=12.4 cm We know the value of h and c. h=6.626 * 10^-34 Js c= 2.997 * 10^8 m/s wavelength=12.4 cm converted to 0.124 m E = [ 6.626 * 10^-34 Js * 2.997 * 10^8 m/s ] / 0.124 m E = 1.60 * 10^-24 J 1.60 * 10^-24 J of energy of exactly one photon of this microwave radiation have.

Answer 2

The energy of the photon emitted is about 1.60 × 10⁻²⁴ Joule

Further explanation

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is :

$\large {\boxed {E = h \times f}}$

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

$\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}$

$\large {\boxed {E = qV + \Phi}}$

E = Energi of A Photon ( Joule )

m = Mass of an Electron ( kg )

v = Electron Release Speed ( m/s )

Ф = Work Function of Metal ( Joule )

q = Charge of an Electron ( Coulomb )

V = Stopping Potential ( Volt )

Let us now tackle the problem !

Given:

λ = 12.4 cm = 12.4 × 10⁻² m

h = 6.63 × 10⁻³⁴ Js

c = 3 × 10⁸ m/s

Unknown:

E = ?

Solution:

$E = h \times \frac{c}{\lambda}$

$E = 6.63 \times 10^{-34} \times \frac{3 \times 10^8}{12.4 \times 10^{-2}}$

$E \approx 1.60 \times 10^{-24} ~ Joule$

Learn more

• Photoelectric Effect : brainly.com/question/1408276
• Statements about the Photoelectric Effect : brainly.com/question/9260704
• Rutherford model and Photoelecric Effect : brainly.com/question/1458544

Answer details

Grade: College

Subject: Physics

Chapter: Quantum Physics

Keywords: Quantum , Physics , Photoelectric , Effect , Threshold , Wavelength , Stopping , Potential , Copper , Surface , Ultraviolet , Light