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olasank [31]
4 years ago
12

A current carrying loop of wire lies flat on a table top. When viewed from above, the current moves around the loop in a counter

clockwise sense. What is the direction of the magnetic field caused by this current, outside the loop? The magnetic field
A) circles the loop in a clockwise direction.
B) points straight up.
C) points straight down.
D) points toward the east.
E) circles the loop in a counterclockwise direction.
Physics
1 answer:
nexus9112 [7]4 years ago
7 0

Answer:

B) points straight up.

Explanation:

As per the rule of Right hand thumb rule we know that magnetic field due to a closed loop is given by the direction of the thumb of right hand when our fingers of right hand is curled in the direction of current in the loop.

Here it is given that current is flowing in the loop in counter clockwise direction.

So here we will curl our fingers in counter clockwise direction so due our thumb will indicate perpendicular to the plane of the loop outwards or straight upwards.

So here correct answer will be

B) points straight up.

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A force of 124 newtons pushed a 12kg object forward 13 meters. How much work is being done?
MariettaO [177]

Answer:

Work = Force * Distance

Here,

force = 124 N

distance = 13m

Thus, Work = 124 * 13 = 1612 joules(J)

5 0
2 years ago
A solenoid with 1000 turns has a cross-sectional area of 7.0 cm2 and length of 25 cm. How much energy is stored in the magnetic
Nimfa-mama [501]

Answer:

The energy stored in the solenoid is 0.18J

Explanation:

We need to obtain the inductance in order to calculate the energy:

L=\µ_o*N^2*\frac{A}{L}\\\\L=4*\pi*10^{-7}*1000^2*\frac{(7.0*10^{-4}m^2)}{25*10^{-2}m}\\L=3.51mH

The energy stored in the solenoid is given by:

U_g=\frac{1}{2}*L*i^2\\\\U_g=\frac{1}{2}*3.51*10^{-3}*10.0^2\\\\U_g=0.18J

3 0
3 years ago
Four 50-g point masses are at the corners of a square with 20-cm sides. What is the moment of inertia of this system about an ax
deff fn [24]

Answer:

moment of inertia I ≈ 4.0 x 10⁻³ kg.m²

Explanation:

given

point masses = 50g = 0.050kg

note: m₁=m₂=m₃=m₄=50g = 0.050kg

distance, r, from masses to eachother = 20cm = 0.20m

the distance, d, of each mass point from the centre of the mass, using pythagoras theorem is given by

= (20√2)/ 2 = 10√2 cm =14.12 x 10⁻² m  

moment of inertia is a proportion of the opposition of a body to angular acceleration about a given pivot that is equivalent to the entirety of the products of every component of mass in the body and the square of the component's distance from the center

mathematically,

I = ∑m×d²

remember, a square will have 4 equal points

I = ∑m×d² = 4(m×d²)

I = 4 × 0.050 × (14.12 x 10⁻² m)²

I = 0.20 × 1.96 × 10⁻²

I =  3.92 x 10⁻³ kg.m²

I ≈ 4.0 x 10⁻³ kg.m²

attached is the diagram of the equation

7 0
3 years ago
If you exert a force on an object in motion you will change its what?
expeople1 [14]
You will change its <span>Velocity</span>
6 0
4 years ago
Read 2 more answers
5. The table shows the total vertical distance a free-falling body travels for each second it falls. About how far does the free
ratelena [41]

Answer:

a. 44 m

Explanation:

We don't have the table but we can still answer since the motion is a free-fall motion.

First of all, we calculate the velocity of the body at time t = 4 s, with the equation

u'=u+gt

where

u = 0 is the initial velocity

g = 9.8 m/s^2 is the acceleration of gravity (we take downward as positive direction)

t is the time

Using t = 4 s,

u'=0+(9.8)(4)=39.2 m/s

Now we can calculate the distance covered during the time t = 4 s and t = 5 s using the other suvat equation

s=u'\Delta t+\frac{1}{2}g\Delta t^2

where

\Delta t = 5-4=1s is the time interval we are considering. Substituting values,

s=(39.2)(1)+\frac{1}{2}(9.8)(1)^2=44 m

4 0
3 years ago
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