Answer:
the required speed/velocity of the stunt double is 13.633 km/h
Explanation:
Given the data in the question;
velocity of train V = 150 km/h
distance = length of train + distance between the tunnel and the end
= 2 km + 20 km = 22 km
first we calculate time t taken by the train to reach the tunnel;
t = distance / velocity
we substitute
t = 22 km / 250 km/h
t = 0.1467 hr
so the velocity of the of the stunt double will be;
velocity = distance / time
we substitute
velocity = 2 km / 0.1467 hr
velocity = 13.633 km/h
Therefore, the required speed/velocity of the stunt double is 13.633 km/h
The next car will have a velocity of 124. The impact of the one car showing newton's law.
We all know that the sound travels faster through solids and then liquids and then through gases.
As far as i know solids are the medium through which the sound travels fast.
But in some websites I saw that as the density increases , the velocity of the sound decreases.If this statement is correct , how come the sound travels fastest through solids (since they have higher density)
From this it is clear that not only sound as compression wave But also in the form of Shear wave travels in Solids
This makes it easier for sound to travel with higher speed in solids
The answer is A ) much hotter
Answer:
Orbital period of satellite is 5.83 x 10³ s
Explanation:
The orbital period of satellite revolving around Earth is given by the equation :
.....(1)
Here R is radius of Earth, h is height of satellite from the Earth's surface, M is mass of Earth and G is gravitational constant.
In this problem,
Height of satellite, h = 500 km = 500 x 10³ m
Substitute 6378.1 x 10³ m for R, 500 x 10³ m for h, 5.972 x 10²⁴ kg for M and 6.67 x 10⁻¹¹ m³ kg⁻¹ s⁻² for G in equation (1).
![T=\sqrt{\frac{4\pi ^{2} [(6378.1+500)\times10^{3} ]^{3} }{6.67\times10^{-11} \times5.972\times10^{24} } }](https://tex.z-dn.net/?f=T%3D%5Csqrt%7B%5Cfrac%7B4%5Cpi%20%5E%7B2%7D%20%5B%286378.1%2B500%29%5Ctimes10%5E%7B3%7D%20%5D%5E%7B3%7D%20%7D%7B6.67%5Ctimes10%5E%7B-11%7D%20%5Ctimes5.972%5Ctimes10%5E%7B24%7D%20%7D%20%7D)
<em>T</em> = 5.83 x 10³ s
