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Komok [63]
3 years ago
11

While riding on an elevator descending with a constant speed of 2.7 m/s , you accidentally drop a book from under your arm. How

long does it take for the book to reach the elevator floor, 1.0 m below your arm?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

0.45 s.

Explanation:

From Newton's equation of motion,

s = ut + 1/2gt²........................ Equation 1

Where s = distance, u = initial velocity, a = acceleration, t = time

Given: s = 1.0 m, u = 0 m/s (dropped from height), g = 9.81 m/s²

Substituting into equation 1,

1 = 0(t) + 1/29.81(t²)

1 = 9.81t²/2

2 = 9.81t²

t² = 2/9.81

t² = 0.204

t = √(0.204)

t = 0.45 s.

Hence it takes 0.45 s for the book to reach the elevator floor.

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Jumping up before the elevator hits. After the cable snaps and the safety system fails, an elevator cab free-falls from a height
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Answer:

a) I = -2257.6 Kg*m/s

b) F = -451,520N

Explanation:

part a.

we know that:

I = P_f-P_i

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so:

I = MV_f-MV_i

where M is the mass, V_f the final velocity and V_i the initial velocity.

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solving for V_i:

V_i = 26.56m/s

Then, replacing in the initial equation:

I = MV_f-MV_i

I = (85kg)(0m/s)-(85kg)(26.56m/s)

I = -2257.6 Kg*m/s

Then, the impulse is -2257.6 Kg*m/s, it is negative because it is upwards.

part b.

we know that:

Ft = I

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solving for F:

F = -451520N

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