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Komok [63]
3 years ago
11

While riding on an elevator descending with a constant speed of 2.7 m/s , you accidentally drop a book from under your arm. How

long does it take for the book to reach the elevator floor, 1.0 m below your arm?
Physics
1 answer:
Angelina_Jolie [31]3 years ago
4 0

Answer:

0.45 s.

Explanation:

From Newton's equation of motion,

s = ut + 1/2gt²........................ Equation 1

Where s = distance, u = initial velocity, a = acceleration, t = time

Given: s = 1.0 m, u = 0 m/s (dropped from height), g = 9.81 m/s²

Substituting into equation 1,

1 = 0(t) + 1/29.81(t²)

1 = 9.81t²/2

2 = 9.81t²

t² = 2/9.81

t² = 0.204

t = √(0.204)

t = 0.45 s.

Hence it takes 0.45 s for the book to reach the elevator floor.

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Answer:

a

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b

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From the question we are told that

   The frequency is  f =  65.4 \  Hz

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   The  mass is  m  =  15.0 \ g  =  0.015 \  kg

Generally the wavelength is mathematically represented as

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=>      T  =  77.172 ^2  *  \frac{  0.015  }{0.590}

=>      T  = 151.41 \  N

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