The final velocity of the train at the end of the given distance is 7.81 m/s.
The given parameters;
- initial velocity of the train, u = 6.4 m/s
- acceleration of the train, a = 0.1 m/s²
- distance traveled, s = 100 m
The final velocity of the train at the end of the given distance is calculated using the following kinematic equation;
v² = u² + 2as
v² = (6.4)² + (2 x 0.1 x 100)
v² = 60.96
v = √60.96
v = 7.81 m/s
Thus, the final velocity of the train at the end of the given distance is 7.81 m/s.
Learn more here:brainly.com/question/21180604
<span>Using Coulomb's law: k*(-0.3)*(-0.3)/(d^2)=19.2
D is the distance between the two negative charges</span>
Answer:
2.09 rad/s
Explanation:
Given that,
A toy car makes 4 laps in 12 s.
We need to find the angular velocity of the toy car. We need to find the angular velocity of the toy car.
4 laps = 25.13 rad
So,
So, the angular velocity of the toy car is 2.09 rad/s.
Answer:
The correct answer is B. 0.64 m/s²
Explanation:
According to the Newton's Second law of motion acceleration of an object by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force.
Mathematically,
F ∝ a
F = ma
Given data:
Force = F = 35 N
Mass = m = 55 kg
acceleration = a = ?
F = ma
a = F/m
a = 35/55
a = 0.64 m/s²
