Answer:
A=0.199
Explanation:
We are given that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=
Total energy of the oscillation=0.51 J
We have to find the amplitude of oscillations.
Energy of oscillator=
Where
=Angular frequency
A=Amplitude

Using the formula



Hence, the amplitude of oscillation=A=0.199
Answer:
Required KVP = 86 KVP (Approx)
Explanation:
Given:
Current KVP = 75 KVP
Find:
KVP required to double exposure
Computation:
According to 15% rule of KVP,
15% change increse in KVP required to get double exposure.
So,
Required KVP = Current KVP + Current KVP(15%)
Required KVP = 75 KVP + 75 (15%)
Required KVP = 75 KVP + 11.25 KVP
Required KVP = 86.25 KVP
Required KVP = 86 KVP (Approx)
Answer:
First option
Explanation:
If the ball is running in a circular motion then its velocity <em>v</em> will be tangency to the circular path.
In this problem the centripetal force that allows the circular movement is the tension <em>T</em> of the rope to which the ball is tied, if the child releases the rope then this tension becomes equal to zero and the circular movement is interrupted.
As the speed <em>v</em> of the ball is always tangential to the circumference at any point of the same, then at the instant in which the rope is released, the ball will follow the same trajectory that it had at that moment, that is, tangential to the circumference.
Observe the attached image.
Therefore the answe is: tangent to the circle
Answer:
Answer 2 is iron.
Answer 3 is magnetic induction.
Explanation:
I hope it's helpful!