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Gelneren [198K]
3 years ago
13

How many grams are in 1.19x10^27 particles of cl2

Chemistry
1 answer:
djverab [1.8K]3 years ago
5 0

Answer:

Option D. 1.40x10^5g

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 particles. This equally means that 1mole of Cl2 contains 6.02x10^23 particles.

1 mole of Cl2 =2 x 35.5 = 71g.

Now, If 71g of Cl2 contains 6.02x10^23 particles,

Then Xg of Cl2 will contain 1.19x10^27 particles i.e

Xg of Cl2 = (71x1.19x10^27)/(6.02x10^23)

Xg of Cl2 = 1.40x10^5g

Therefore, 1.40x10^5g of Cl2 contain 1.19x10^27 particles

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How many moles of silver can be produced from silver nitrate from 1 mole of zinc?
jasenka [17]

Answer:

Answer: 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.

Explanation:

To calculate the moles of silver formed and the moles of excess reagent left after the reaction, we need to balance the equation first and need to find the limiting and excess reagent.

The balanced chemical equation is:

Zn + 2AgNO3 ---> Zn (NO3)2 +2Ag

By Stoichiometry:

2 moles of Silver nitrate reacts with 1 mole of Zinc metal

So, 6.5 moles of silver nitrate will react with = 1/2 x 6.5 = 3.25 moles of zinc metal

The required amount of zinc metal is less than the given amount of zinc metal,  hence, it is considered as an excess reagent.

Therefore, silver nitrate is the limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of silver nitrate produces 2 moles of silver metal

So, 6.5 moles of silver nitrate will produce = 2/2 x 6.5 = 6.5moles of silver metal.

Number of moles of excess reagent left after the completion of reaction = (3.8 - 3.25)moles = 0.55 moles

Hence, 6.5 moles of silver metal is formed in the given chemical reaction. The moles of excess reagent left are 0.55 moles.

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What do you mean bro

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The value of Zeff for a valence electron in an atom of silicon is?
lutik1710 [3]

Zeff is the effective nuclear charge wherein, Z resembles the number of protons in the nucleus while S corresponds to the number of non-valence electrons.

Zeff = Z - S

Silicon has 14 protons; its electron configuration is [Ne] 3s2 3p2. Its non-valence electrons is in the n = 1 and n =2 shells. There are 2 electrons in n = 1 and 8 in n = 2, so there are a total of 10 non-valence electron.

<span><span>Z<span>eff</span></span>= 14−10= 4</span>

So, the answer is 4.
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