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wlad13 [49]
3 years ago
8

One liter of gas A at 1.0 atm pressure has a temperature of 25°C while the same volume and pressure of gas B has a temperature o

f 50°C. What else do you know about these two gases?
A) There are twice as many moles of gas B than gas A.
B) Gas A has twice the molar mass of gas B.
C) Gas A has more kinetic energy than gas B.
D) Gas B has more kinetic energy than gas A.
Chemistry
1 answer:
kakasveta [241]3 years ago
5 0

Answer:

b

Explanation:

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How many atoms of Pb are there?
jeka94

Answer: i believe it is

602,000,000,000,000,000,000,000 atoms

Explanation:

6.02×1023 atoms/mole

6 0
3 years ago
Consider the reaction: 2 SO2(g) + O2(g) <----> 2 SO3. If, at equilibrium at a certain temperature, [SO2] = 1.50 M, [O2] =
vlada-n [284]

Answer:

5.79

Explanation:

The following data were obtained from the question:

Concentration of SO2, [SO2] = 1.50 M

Concentration of O2, [O2] = 0.120 M

Concentration of SO3, [SO3] = 1.25 M

Equilibrium constant, (K) =..?

The balanced equation for the reaction is given below:

2SO2(g) + O2(g) <==> 2SO3(g)

From the balanced equation, the equilibrium constant K is written as follow:

K = [SO3]²/ [SO2]²• [O2]

With the above, the value of the equilibrium constant, K can be obtained as follow

K = [SO3]²/ [SO2]²• [O2]

K = (1.25)² / (1.50)² × 0.120

K = 1.5625 / ( 2.25 x 0.120)

K = 5.79

Therefore, the equilibrium constant is 5.79.

7 0
3 years ago
Noclouttrio -inta ………………….!.!.!!..!
Ronch [10]

Answer:

3 more brlst

Explanation:

4 0
3 years ago
PLS HELP! If I have 17 moles of gas at a temperature of 67°C, and a pressure of 5.34 atmospheres, what is the volume of the gas?
sveta [45]

Answer: If I have 17 moles of gas at a temperature of 67°C, and a pressure of 5.34 atmospheres, what is the volume of the gas? write down all the givens of the problem

8 0
3 years ago
Read 2 more answers
In a coffee-cup calorimeter, 1 mol NaOH and 1 mol HBr initially at 22.5 oC (Celsius) are mixed in 100g of water to yield the fol
zavuch27 [327]

Answer:

ΔH = -55.92 kJ

Explanation:

<u>Step 1:</u> Data given

1 mol NaOH and 1 mol HBr initially at 22.5 °C are mixed in 100g of water

After mixing the temperature rises to 83 °C

Specific heat of the solution = 4.184 J/g °C

Molar mass of NaOH = 40 G/mol

Molar mass of HBr = 80.9 g/mol

<u>Step 2: </u>The balanced equation

NaOH + HBr → Na+(aq) + Br-(aq) + H2O(l)

<u>Step 3:</u> mass of NaOH

Mass = moles * Molar mass

Mass NaOH = 1 * 40 g/mol

Mass NaOH = 40 grams

Step 4: Mass of HBr

Mass HBr = 1 mol * 80.9 g/mol

Mass HBr = 80.9 grams

Step 5: Calculate ΔH

ΔH = m*c*ΔT

ΔH= (100 + 40 + 80.9) * 4.184 * (83-22.5)

ΔH= 220.9 * 4.184 * 60.5

ΔH= 55916.86 J = 55.92 kJ

Since this is an exothermic reaction, the change in enthalpy is negative.

ΔH = -55.92 kJ

4 0
4 years ago
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