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3 years ago

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Certain elements in the periodic table are referred to as inert or noble gases. What is the reason for this?

1 answer:

Katyanochek1 [597]3 years ago

3 0

Answer:

The elements of group 0 are referred to as noble or inert gases because they're so "majestic" that, generally, they don't react with anything and we're believed to be rare elements e.g Neon, argon, krypton, xenon and radon.

Explanation:

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What type of chemical reaction is CaCaI2 + F2 = CaF2 + CI2

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58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,

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<em><u>Answer and Explanation:</u></em>

$Greetings!$

$Let's~answer~your~question!$

$Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.$

$\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}$

<em><u>For % of N2 gas: </u></em>

<em><u /></em> $100\% - (5\% + 12\%) = 83\% ~N2$ <em><u /></em>

<em><u /></em>

<em><u /></em> $PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm$ <em><u /></em>

<em><u /></em> $PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm$ <em><u /></em>

<em><u /></em> $~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm$ <em><u /></em>

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4 years ago

Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.

Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

$\%C_E = \frac{E}{T} * 100\%$

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In $(Ca(OH)_2)$

The amount of all elements is: (i.e formula mass of $(Ca(OH)_2)$ )

$T = 1 * Ca + 2 * H + 2 * O$

$T = 1 * 40 + 2 * 1 + 2 * 16$

$T = 74$

The amount of calcium is: (i.e formula mass of calcium)

$E = 1 * Ca$

$E = 1 * 40$

$E = 40$

So, the percentage component of calcium is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{40}{74} * 100\%$

$\%C_E = \frac{4000}{74}\%$

$\%C_E = 54.05\%$

The amount of hydrogen is:

$E = 2 * H$

$E = 2 * 1$

$E = 2$

So, the percentage component of hydrogen is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{2}{74} * 100\%$

$\%C_E = \frac{200}{74}\%$

$\%C_E = 2.70\%$

Similarly, for oxygen:

The amount of oxygen is:

$E = 2 * O$

$E = 2 * 16$

$E = 32$

So, the percentage component of oxygen is:

$\%C_E = \frac{E}{T} * 100\%$

$\%C_E = \frac{32}{74} * 100\%$

$\%C_E = \frac{3200}{74}\%$

$\%C_E = 43.24\%$

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3 years ago