Answer:
64.7g
Explanation:
The balanced chemical equation of this question is as follows;
AlI + HgCl2 → HgI + AlCl2
Based on the above equation, 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide).
Using mole = mass/molar mass to convert mass of HgI to moles.
Molar mass of HgI = 200.59 + 127
= 327.59g/mol
Mole = 138/327.59
= 0.42mol
- If 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide)
- Then 0.42 mol of HgI will be produced by 0.42mol of AlI.
Using mole = mass/molar mass
Mass = mole × molar mass
Molar mass of AlI = 27 + 127
= 154g/mol
Mass of AlI = 0.42 × 154
= 64.7g of AlI
The answer here is neutrons
Answer:
2.35 M
Explanation:
Molarity is mol/L of solution. We have to convert the g to mol and the mL to L. G to mol uses the molar mass of the compound. The molar mass of NaNO₃ is 85.00g/mol.
Then you have to convert mL to L.
Now divide the mol by the L.
Round to the smallest number of significant figures = 2.35M
The formula for that compound is AlN
