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Gnesinka [82]
3 years ago
10

Select the correct answer. Two charged objects, A and B, exert an electric force on each other. What happens if the distance bet

ween them is increased? A. The charge on B decreases. B. The charge on B increases. C. The electric force between them decreases. D. The electric force between them increases.
Chemistry
1 answer:
VikaD [51]3 years ago
7 0

Answer:

The electric force between them decreases

Explanation:

The force between two charged particle is given by :

F=\dfrac{kq_1q_2}{r^2}

Where

r is the distance between charges

If the distance between the charges is increased, the electric force gets decreased as there is an inverse relation between force and distance.

Hence, the correct option is (c) "The electric force between them decreases"

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How many moles are in 8.32 x 1024 molecules of CO2.
Andrews [41]

Answer:

<h2>13.82 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.32 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 13.820598...

We have the final answer as

<h3>13.82 moles</h3>

Hope this helps you

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Answer:

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Explanation:

i think leter B it because

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lbvjy [14]
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2 years ago
The enthalpy of fusion of methanol (CH3OH) is 3.16 kJ/mol. How much heat would be absorbed or released upon freezing 25.6 grams
Verdich [7]

Answer:

There is  2.52 kJ of energy released (option 4)

Explanation:

Step 1: Data given

The enthalpy of fusion of methanol (CH3OH) is 3.16 kJ/mol

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Molar mass of methanol = 32.04 g/mol

Step 2: Calculate moles of methanol

Moles methanol = mass methanol / molar mass methanol

Moles methanol = 25.6 grams / 32.04 g/mol

Moles methanol = 0.799 moles

Step 3: Calculate energy transfer

Energy  transfer = moles * enthalpy of fusion

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Energy = 2.52 kJ released

There is  2.52 kJ of energy released

6 0
3 years ago
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