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4 years ago

Choose the correct word from the drop-down menu to complete each sentence.

Chemistry

2 answers:

marin [14]4 years ago

5 0

Answer:

1 humus

2 loam

3 sand

4 slit

5 clay

Explanation:

shepuryov [24]4 years ago

4 0

Answer:

1) is humus

2)is loam

3)is sand

4)is silt

5)is clay

Explanation:

I did the quiz and got it right

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Express in scientific notation 800678

jasenka [17]

8 10^5 hoped that helped

6 0

3 years ago

When dissolving gases in water, the amount dissolving (decreases, does not change, increases) when the pressure is increased?

algol13

Increasing because more is being forced into liquid phase

4 0

4 years ago

Can someone help me out

Xelga [282]

Yea the first one my guy

4 0

3 years ago

What is the value for the kinetic energyfor a n = 2 Bohr orbit electron in Joules?

Vladimir [108]

Answer:

K.E. = 5.4362 × 10⁻¹⁹ J

Explanation:

The expression for Bohr velocity is:

$v=\frac{Ze^2}{2 \epsilon_0\times n\times h}$

Applying values for hydrogen atom,

Z = 1

Mass of the electron ( $m_e$ ) is 9.1093×10⁻³¹ kg

Charge of electron (e) is 1.60217662 × 10⁻¹⁹ C

$\epsilon_0$ = 8.854×10⁻¹² C² N⁻¹ m⁻²

h is Plank's constant having value = 6.626×10⁻³⁴ m² kg / s

We get that:

$v=\frac {2.185\times 10^6}{n}\ m/s$

Given, n = 2

So,

$v=\frac {2.185\times 10^6}{2}\ m/s$

$v=1.0925\times 10^6\ m/s$

Kinetic energy is:

$K.E.=\frac {1}{2}\times mv^2$

So,

$K.E.=\frac {1}{2}\times 9.1093\times 10^{-31}\times ({1.0925\times 10^6})^2$

K.E. = 5.4362 × 10⁻¹⁹ J

3 0

3 years ago

An experimenter found that for the hydrolysis of lactose, ΔH° = +0.44 kJ mol–1 and ΔS° = +0.031 kJ mol–1 K–1. ΔG°for this reacti

Ksivusya [100]

Answer:

ΔG° = -8.8 kJ/mol

Explanation:

The standard Gibbs free energy of reaction (ΔG°) can be calculated using the following expression.

ΔG° = ΔH° - T.ΔS°

where,

ΔH°: standard enthalpy of reaction

T: absolute temperature

ΔS°: standard entropy of reaction

At 298 K (the temperature that is usually used), ΔG° for the hydrolysis of lactose is:

ΔG° = ΔH° - T.ΔS°

ΔG° = 0.44 kJ/mol - 298 K × 0.031 kJ/mol.K

ΔG° = -8.8 kJ/mol

7 0

3 years ago