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Nadya [2.5K]
3 years ago
7

at a pressure of 101.3 kilopascal and a temperature of 373 K, heat is removed from a sample of water vapor, causing the sample t

o change from the gaseous phase to the liquid phase. This phase change is represented by the equation H20(g) -> H20(l) + heat. Determine the total amount of heat released by 5.00 grams of water vapor during the phase change shown in the given experiment
Chemistry
1 answer:
Kruka [31]3 years ago
8 0

Answer:

The amount of heat released is 11.3 KJ

Explanation:

H20(g) -> H20(l) + heat

This reaction is changing state from gaseous to liquid without changing the temperature. This heat is know as Latent heat. It is the energy required for a phase change.

Heat released by 5 g of water vapor (Q) = M ×  L

where M = mass of vapor

L= latent heat

Latent heat can be divide into 2

  1. Latent heat of fusion
  2. Latent heat of vaporization

Since we are change the gaseous state to liquid, we will be working with Latent heat of vaporization which has a value of 22.6 x 10 ∧5 J/kg

                                     (Q) = M ×  L

                                           = 0.005 x 22.6 x 10 ∧5

                                           = 11300 J

                                           = 11.3 KJ

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3 years ago
Calculate the equilibrium constant for the reaction between fe2+(aq) and zn(s) under standard conditions at 25∘c.
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7 0
3 years ago
An aqueous solution containing 17.5 g of an unknown molecular (nonelectrolyte) compound in 100.0 g of water has a freezing point
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Answer:

molar mass = 180.833 g/mol

Explanation:

  • mass sln = mass solute + mass solvent

∴  solute: unknown molecular (nonelectrolyte)

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∴ mass solute = 17.5 g

∴ mass solvent =  100.0 g = 0.1 Kg

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freezing point:

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∴ ΔTc = -1.8 °C

∴ Kc H2O = 1.86 °C.Kg/mol

∴ m: molality (mol solute/Kg solvent)

⇒ m = ( - 1.8 °C)/( - 1.86 °C.Kg/mol)

⇒ m = 0.9677 mol solute/Kg solvent

  • molar mass (Mw) [=] g/mol

∴ mol solute = ( m )×(Kg solvent)

⇒ mol solute = ( 0.9677 mol/Kg) × ( 0.100 Kg H2O )

⇒ mol solute = 0.09677 mol

⇒ Mw solute = ( 17.5 g ) / ( 0.09677 mol )

⇒ Mw solute = 180.833 g/mol

6 0
3 years ago
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