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4 years ago

B. CO

Physics

2 answers:

jekas [21]4 years ago

6 0

The answer is 0.6 ms

Hunter-Best [27]4 years ago

5 0

Answer:

0.6 m/s

Explanation:

2Hz = 2^-1 = 2 /s

30cm = .3m

Velocity is in the units m/s, so multiplying wavelength in meters by the frequency will give you the velocity.

(.3m)*(2 /s) = 0.6 m/s

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Two stretched copper wires both experience the same stress. The first wire has a radius of 3.9×10-3 m and is subject to a stretc

maw [93]

The stretching force acting on the second wire, given the data is 588 N

<h3>Data obtained from the question</h3>

Radius of fist wire (r₁) = 3.9×10⁻³ m
Force of first wire (F₁) = 450 N
Radius of second wire (r₂) = 5.1×10⁻³ m
Force of second wire (F₂) =?

<h3>How to determine the force of the second wire</h3>

F₁ / r₁ = F₂ / r₂

450 / 3.9×10⁻³ = F₂ / 5.1×10⁻³

cross multiply

3.9×10⁻³ × F₂ = 450 × 5.1×10⁻³

Divide both side by 3.9×10⁻³

F₂ = (450 × 5.1×10⁻³) / 3.9×10⁻³

F₂ = 588 N

Learn more about spring constant:

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7 0

2 years ago

What determines the precision of a measurement?

hram777 [196]

Answer:

Precision is determined by a statistical method called a standard deviation To determine if a value is precise find the average of your data, then subtract each measurement from it

4 0

3 years ago

A particle's velocity is described by the function vx = kt 2 m/s, where k is a constant and t is in s. The particle's position a

vodomira [7]

Answer:

The value of the constant k is 2

Explanation:

We have the equation of the velocity $v_{x}$ = kt² , where k

is constant and t is the time in second

The particle's position at $t_{0}$ = 0 is $x_{0}$ = -9 m

The particle's position at $t_{1}$ = 3 s is $x_{1}$ = 9 m

We need to find the value of the constant k

The relation between the velocity and the displacement in a particular

time is x = $\int\ {v_{x} } \, dt$

Remember in integration we add power by 1 and divide the expression

by the new power

→ x = $\int\ {kt^{2} } \, dt=\frac{1}{3}kt^{3}+c$

c is the constant of integration to find it substitute the initial value of x

and t in the equation of x

→ $t_{0}$ = 0 , $x_{0}$ = -9 m

→ -9 = $\frac{1}{3}$ k (0)³ + c

→ -9 = c

Substitute the value of c in the equation of x

→ x = $\frac{1}{3}$ k t³ - 9

To find k substitute the values of $t_{1}$ = 3 s , $x_{1}$ = 9 m

→ 9 = $\frac{1}{3}$ k (3)³ - 9

→ 9 = $\frac{1}{3}$ (27) k - 9

→ 9 = 9 k - 9

Add 9 to both sides

→ 18 = 9 k

Divide both sides by 9

→ k = 2

<em>The value of the constant k is 2</em>

5 0

4 years ago

Why is the weight of a body more at the pole than at the equator of the earth ??

Yuki888 [10]

At pole the gravitation is more than that of equator .

And according to newtons second law

Force=Mass×Acceleration

And

$\\ \sf\longmapsto F\propto a$

Hence force varies directly with acceleration hence weight will be more .

3 0

3 years ago

Read 2 more answers

A magnet that is dropped may lose its ______.

Nikitich [7]

Answer:

Permanent magnets can lose their magnetism if they are dropped or banged on enough to bump their domains out of alignment

Explanation:

3 0

3 years ago