All categories

4 years ago

The distance between your and your is displacement

1 answer:

4 0

The distance between your initial position and your final position is displacement. Often denoted by $x$ or Δ $x$

You might be interested in

Two gravitational forces act on a particle, in perpendicular directions. to find the net force, can we add the magnitudes of tho

Anna71 [15]

No, we can not add the magnitudes of those two forces.

<h3>What is Gravitational Force?</h3>

An attractive force between masses is a gravitational force. According to Isaac Newton's second law, F = ma, a gravitational force generates an acceleration just like all other forces do. Remember that according to Newton's second law, a body will accelerate if there is a net force acting on it in an inertial frame of reference (a coordinate system travelling at a constant speed). According to Newton's Universal Law of Gravitation, when two bodies, such as the Earth and the Sun, are in close proximity to one another, an attractive force naturally attracts them. This attraction results in an acceleration of the two objects.

To learn more about Gravitational Force, visit:

brainly.com/question/12528243

#SPJ4

6 0

2 years ago

Choose a starting point in United states to sail back to Africa. Determine the wind and current correction vectors that would ta

statuscvo [17]

Answer:

I personally think the answer is 5 because if you look at it its 5

7 0

3 years ago

The uncertainty in the position of an electron along an x axis is given as 68 pm. What is the least uncertainty in any simultane

umka21 [38]

Answer:

$\Delta p_x=7.75\times 10^{-25}\ kg-m/s$

Explanation:

Given that,

The uncertainty in the position of an electron along the x-axis is, $\Delta x=68\ pm=68\times 10^{-12}\ m$

We need to find the east uncertainty in any simultaneous measurement of the momentum component of this electron.

We know that the Heisenberg's uncertainty principle gives the relation between the uncertainty in position and the momentum of electron as :

$\Delta p_x{\cdot}\Delta x\ge \dfrac{h}{4\pi }$

Putting all the values, we get :

$\Delta p_x{\cdot}\ge \dfrac{h}{4\pi \Delta x}\\\\\Delta p_x \ge \dfrac{6.63\times 10^{-34}}{4\pi \times 68\times 10^{-12}}\\\\\Delta p_x\ge 7.75\times 10^{-25}\ kg-m/s$

So, the momentum component of this electrons is greater than $7.75\times 10^{-25}\ kg-m/s$ .

6 0

4 years ago

Are cells made of tisse?

zepelin [54]

Answer:

Yes

Explanation:

Cells make up tissues. Hope this helped

5 0

3 years ago

Read 2 more answers

How can the distance between the first bright band and the central band be increased in a double-slit experiment?

Strike441 [17]

Answer:

Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.

Explanation:

The distance $y$ from the central band to the first bright band is given by

$y = \dfrac{ \lambda D}{d}$

where $\lambda$ is the wavelength of light (or any particle), $D$ is the distance to the screen, and $d$ is the slit separation.

From this equation we see that, by increasing the wavelength $\lambda$ , increasing the distance from the screen $D$ , and decreasing the slit separation $d$ , we increase the distance between the first bright band and the central band.

Therefore, the 2nd choice "<em>Decrease the slit separation, increase the distance of the screen from the slits, and increase the wavelength.</em>" is correct.

8 0

4 years ago