Answer:
35.7 kg
Explanation:
We are given that
Left scale reads =200N
Right scale reads=150 N
We have to find the mass in kg.
We know that
Weight of child= Sum of two scales=200+150=350 N
Acceleration due to gravity=
We know that
Weight= mg
Using the formula


Hence, the mass of child=35.7 kg
Answer:
The stiffness of one of the individual spring is 390 N/m.
Explanation:
It is given that 43 identical springs are placed side-by-side and connected to a large massive block.
The stiffness of the 43 spring combination is 16770 N/m
We need to find the stiffness of one of the individual springs. Let k is the stiffness of one spring. The effective spring stiffness of this width spring is given by :



k = 390 N/m
So, the stiffness of one of the individual spring is 390 N/m. Hence, this is the required solution.
B) 20 cm
The height and distance will be the same. Only the image will be laterally inverted.