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Dennis_Churaev [7]
4 years ago
8

Diferencie energia cinética de energia potencial gravitacional.

Physics
1 answer:
Vikentia [17]4 years ago
4 0

Answer:

Featured snippet from the web

The atoms and molecules in it are in constant motion. The kinetic energy of such a body is the measure of its temperature. Potential energy is classified depending on the applicable restoring force. Gravitational potential energy – potential energy of an object which is associated with gravitational force

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Answer:

Explanation:

mass of the ball = 146 g = 146 / 1000 = 0.146 kg

initial speed of the ball = 40.6 m/s

final speed of the ball = - 45.1 m/s

time of impact = 1.05 ms = 1.05 / 1000 = 0.00105 s

impulse, Ft = change in momentum = mv - mu = m (v-u)

F = m (v - u) / t = 0.146 kg ( -45.1 -40.6) / 0.00105 s = -11916.4 N

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A ball rolls of buildings that is 100m high calculate the time that it takes for ball to hit the ground​
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Answer:

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2000=v2

V=44

V=u+at

44/10=t

T=4.4seconds

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3 years ago
Complete the sentence to explain when waves interact.
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Answer:

Waves interact with objects and other waves.

Explanation:

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3 years ago
The park has added two more cars to the already existing roller coaster. If the park wants to maintain the speed of the roller c
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D because friction will slow it down going up hills (for safety reasons) and you go really fast going down.
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Read 2 more answers
A car (mass 1200 kg, speed 100 km/h) and a truck (mass 2800 kg, speed 50 km/h) are moving in the same direction along a highway.
Sloan [31]

Answer:

Speed of the wreck after the collision is 65 km/h

Explanation:

When a car hits truck and sticks together, the  collision would be totally inelastic.  Since the both the vehicles  locked  together, they have the same final velocity.

Mass of car  m_{1}=1200 kg

Mass of truck m_{2}=2800 kg

Initial speed of the car u_{1}=100 km /h

Initial speed  of the truck u_{2}=50 km /h

The final velocity of the wreck will be

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

since final speed are same, v_{1}=v_{2}=v

m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v

1200\times 100 +2800 \times 50 =(1200+2800)v\\v=\frac{260000}{4000} \\v=65 km/h

5 0
3 years ago
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