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3 years ago

Hey, can someone help me with question 19.

Physics

1 answer:

Anit [1.1K]3 years ago

3 0

HI!

Transformers are devices used in electrical circuits to change the voltage of electricity flowing in the circuit.

Meter are typically calibrated in billing units, the most common one being the kilowatt hour (kWh)

Distribution Panel (also known as panel board, breaker panel, or electric panel) is a component of an electricity supply system that divides an electrical power feed into subsidiary circuits, while providing a protective fuse or circuit breaker for each circuit in a common enclosure.

I hope this helped !

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A 1,383 kg purple car is driving southbound on a road and collides with a 1,827 kg orange car, that was traveling 31.87 m/s east

user100 [1]

Answer:

Explanation:

We shall apply work energy theorem to calculate the initial velocity just after the collision .

Their kinetic energy will be equal to work done by friction .

force of friction = μ mg , where μ is coefficient of friction , m is total mass and g is acceleration due to gravity

force = .463 x 3210 x 9.8

= 14565.05 N

work done = force x displacement

= 14565.05 x 14.54 = 211775.88 J

now applying work energy theorem

1/2 m v² = 211775.88 , m is composite mass , v is velocity just after the collision

.5 x 3210 x v² = 211775.88

v² = 131.94

v 11.48 m /s

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3 years ago

g (a) Calculate the speed of a proton that is accelerated from rest through a potential difference of 127 V. km/s (b) Calculate

Kisachek [45]

Answer:

Explanation:

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3 years ago

Figure 1 shows the kinetic energy as a function of time for a 2kg object that is released from rest and falls toward Earth’s sur

garri49 [273]

Answer:

The answer is 1400 J, according to my Physics teacher.

Explanation:

You need to take into account everything that is listed in the question; it's important to remember that the question is asking about the change in gravitational potential energy of the object-object-Earth system from 0s to 10s, not 0s to 20s. :)

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3 years ago

Anna Litical is practicing a centripetal force demonstration at home. She fills a bucket with water, ties it to a strong rope, a

dlinn [17]

Answer:

Explanation:

Suppose when bucket is half full it has a mass of 2 m rotating in a circle of radius r

When Bucket is quarter full then it has a mass of m rotating in a circle of radius r.

When an object moves in a circular path then it experiences an inward force which is given by

$F_1=\frac{2mv^2}{r}$

where v=velocity of bucket

Force in case 2 is given by

$F_2=\frac{mv^2}{r}$

Thus $F_1=2F_2$

therefore force required in half bucket is more than force required in quarter bucket full.

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4 years ago

The specific heat capacity of sea water is 4100 J/Kg°C and the boiling point of 100.6 °C. (i) Calculate the energy required to r

maw [93]

Answer:

334.314 (kJ)

Explanation:

1) the formula for the required energy is: Q=c*m(Bp-t), where c - 4100 J/kg*C; m - 0.9 kg; Bp - 100.6 C; t - 10 C.

2) according to the formula above:

Q=4100*0.9*(100.6-10)=41*9*906=334314 (J).

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3 years ago