AgNO3+NaCl yields AgCl+NaNo3 (reduction)
...that's the only one I know
In order to compute the mass of each solute in the sample, we simply multiply the percentage mass of each solute with the total mass of the solution. This is ad such:
Mass (NaCl) = 0.0486 x 294
Mass (NaCl) = 14.29 grams
Mass(Na₂CO₃) = 0.0754 x 294
Mass(Na₂CO₃) = 22.17 grams
You basically just multiply those two and you get your answer that simple hope that helps
