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oksano4ka [1.4K]
3 years ago
12

In an inertia balance, a body supported against gravity executes simple harmonic oscillations in a horizontal plane under the ac

tion of a set of springs. If a 1.00-kg body vibrates at 1.00 Hz, a 2.00-kg body will vibrate at Group of answer choices
Physics
1 answer:
sveticcg [70]3 years ago
4 0

Answer;

a 2.00-kg body will vibrate at 0.707Hz

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Which of the following is the correct SI unit to measure of rope?
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Hello!

The answer should be the third option.

Explanation: Because the meters is the correct SI unit to measure of rope. And thank you for posting at here on Brainly. And have a great day! -Charlie

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The wheels of a car have radius 12 in. and are rotating at 600 rpm. Find the speed of the car in mi/h.
guajiro [1.7K]

Answer:

21.4 mph

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What relationship between the sun and earth did copernicus formulate?
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Answer:

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A motorcycle accelerates from at a rate of 4m/s 2 while traveling 60m what it’s the motorcycles velocity at the end of this moti
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5 0
3 years ago
A skydiver of mass 80.0 kg jumps from a slow-moving aircraft and reaches a terminal speed of 50.0 m/s. (a) What is her accelerat
kirill [66]

Answer:

6.22²

Explanation:

Given that

Mass of the skydiver, m = 80 kg

Terminal speed of the skydiver, v(f) = 50 m/s

Speed of the skydiver, v(i) = 30 m/s

Acceleration of the skydiver, a = ?

To solve this, we use the formula

W - k v² = ma, where

W = weight of the skydiver

k = constant

v = speed of the skydiver

m = mass of the skydiver

So, if we substitute the values into it we have

W = mg = 80 * 9.8 = 784 N

784 - k 50² = 80 *0

784 - 2500k = 0

784 = 2500k

k = 0.3136

Now, we use this value of k to find the needed acceleration using the same formula at a speed of 30 m/s

784 - 0.3136 * 30² = 80 * a

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497.76 = 80a

a = 497.76 / 80

a = 6.22 m/s²

Thus, we can conclude that the acceleration when the speed of the skydiver is 30 m/s, is 6.22 m/s²

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3 years ago
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