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vodomira [7]
3 years ago
13

A bus is moving and has 500000 joules of kinetic energy. The brakes are applied and the bus stops. How much work is needed to st

op the bus?
Physics
1 answer:
Bad White [126]3 years ago
8 0
For the work-energy theorem, the work needed to stop the bus is equal to its variation of kinetic energy:
W=K_f - K_i
where
W is the work
Kf is the final kinetic energy of the bus
Ki is the initial kinetic energy of the bus

Since the bus comes at rest, its final kinetic energy is zero: K_f = 0, so the work done by the brakes to stop the bus is
W=-K_i = -500000 J
And the work done is negative, because the force applied by the brake is in the opposite direction to that of the bus motion.
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If you observe an object in the universe that is roughly 8 megaparsecs in size, what is the object most likely to be?
Dmitrij [34]

E. Galaxy Cluster

Explanation:

A galaxy cluster, or cluster of galaxies, is a structure that consists of anywhere from hundreds to thousands of galaxies that are bound together by mutual gravity.

A megaparsec is a million parsecs and there are about 3.3 light years in a mega-parsec. Parsec is rather a natural distance unit for astronomers. The standard abbreviation of a mega-parsec is Mpc.

A parsec is approximately 3.09 x 1016 meters, a megaparsec is about 3.09 x 1022 meters.

Hence, 8 megaparsecs is gigantic size and that can be only of a galaxy cluster consisting of hundreds and thousands of galaxies bounded together.

Keywords: galaxies, parsec, megaparsec, galaxy cluster

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4 0
3 years ago
A spherical shell of radius 9.0 cm carries a uniform surface charge density σ= 9.0 nC/m2. The electric field at r= 9.1 cm is app
maria [59]

Answer:

995.12 N/C

Explanation:

R = 9 cm = 0.09 m

σ = 9 nC/m^2 = 9 x 10^-9 C/m^2

r = 9.1 cm = 0.091 m

q = σ x 4π R² = 9 x 10^-9 x 4 x 3.14 x 0.09 x 0.09 = 9.156 x 10^-10 C

E = kq / r^2

E = ( 9 x 10^9 x 9.156 x 10^-10) / (0.091 x 0.091)

E = 995.12 N/C

8 0
3 years ago
What is the function of the lens of an eye
KATRIN_1 [288]
The lens changes the focal distance of the eye so that you can focus on images/objects. 
8 0
4 years ago
Read 2 more answers
Question 2.
boyakko [2]

The tensile stress of the wire supporting 2 kg mass is determined as 6.1 x 10⁷ N/m².

<h3>Tensile stress of the wire</h3>

The tensile stress of the wire is calculated as follows;

σ = F/A

where;

  • A is area of the wire

A = πr² = πD²/4

where;

  • D is diameter = 0.64 mm

A = π x (0.64 x 10⁻³)²/4

A = 3.22 x 10⁻⁷ m²

σ = F/A = (mg)/A = (2 x 9.8)/( 3.22 x 10⁻⁷)

σ = 6.1 x 10⁷ N/m²

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3 0
2 years ago
a train has an initial velocity of 30 m/s. If the train accelerates uniformly at a rate of 6.3 m/s ^ for 2.8 seconds what is the
Annette [7]

T

Answer:

the velocity is a second final to initial velocity of 39

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