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3 years ago

What would be the force required to accelerate an object that weighs 35 N up at a rate of .60 m/s^2?

Physics

1 answer:

natta225 [31]3 years ago

3 0

Answer: $2.14\ N$

Explanation:

Given

Force required to accelerate the object at the rate of $0.6\ m/s^2$

The weight of the object is $W=35\ N$

Mass of the object can be identified by dividing the weight by acceleration due to gravity

$\Rightarrow m=\dfrac{W}{g}\\\\\Rightarrow m=\dfrac{35}{9.8}\\\\\Rightarrow m=3.57\ kg$

$\therefore \text{Force F=}m\times a\\\Rightarrow F=3.57\times 0.6\\\Rightarrow F=2.14\ N$

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elena55 [62]

Answer:

so length of the fence is 250 feet

Explanation:

Given data

fencing (L) = 500 feet

enclose the garden = 3 sides

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solution

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so we say

df/dx = ƛ × dL/dx

y = ƛ × 1

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from equation 1 we can say

2 ƛ + 2 ƛ = 500

so ƛ = 500/4 = 125

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3 years ago

madam [21]

Answer:

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4 years ago

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3 years ago

Read 2 more answers

If a mass of 76 kg acts downward 0.38 m from the axis of rotation on one end of a board and another force of 129 N also acts dow

Semenov [28]

Answer:

y = 2.196 m

Explanation:

Mass, m = 76 kg

distance from axis of rotation, x = 0.38 m

Second Force, F = 129 N

moment arm of the second force, y = ?

Now, equating moments for the equilibrium

So,

m g × x = F x y

76 x 0.38 x 9.81 = 129 x y

$y = \dfrac{76\times 0.38\times 9.81}{129}$

y = 2.196 m

Hence, the length of the moment arm is equal to 2.196 m.

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