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Tanya [424]
3 years ago
7

What would be the force required to accelerate an object that weighs 35 N up at a rate of .60 m/s^2?

Physics
1 answer:
natta225 [31]3 years ago
3 0

Answer: 2.14\ N

Explanation:

Given

Force required to accelerate the object at the rate of 0.6\ m/s^2

The weight of the object is W=35\ N

Mass of the object can be identified by dividing the weight by acceleration due to gravity

\Rightarrow m=\dfrac{W}{g}\\\\\Rightarrow m=\dfrac{35}{9.8}\\\\\Rightarrow m=3.57\ kg

\therefore \text{Force F=}m\times a\\\Rightarrow F=3.57\times 0.6\\\Rightarrow F=2.14\ N

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What distance will be traveled if you are going 120km/hr for 30 min?
nikklg [1K]

Answer:

60 km

Explanation:

For an object (or a person, such as in this case) moving at constant speed, the speed is equal to the ratio between the distance travelled and the time taken:

v=\frac{d}{t}

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v is the speed

d is the distance

t is the time taken

In this case, we have:

v = 120 km/h is the speed

t = 30 min = 0.5 h is the time taken

Therefore, we can rearrange the equation to find the total distance travelled:

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3 0
3 years ago
A body accelerates uniformly from rest at 2ms² for 5 seconds . calculate its average velocity in this time.​
timama [110]

Answer:

0.4

Explanation:

average velocity =d/t

2/5=0.4

0.4m

7 0
3 years ago
Which method is not a technique currently used by ocean scientists to map the topography of the ocean floor?
raketka [301]

Answer:

Magnetometer

Explanation:

Magnetometer technique is not using by scientists for studying the ocean floor.The scientists currently is using SONAR ( sound navigation and ragging) technique for studying the ocean floor.SONAR is used sound waves sound waves for studying the ocean floor or we can say that SONAR is based on sound propagation.

Therefore answer is Magnetometer

4 0
3 years ago
A hot-air balloon plus cargo has a mass of 308 kg and a volume of 2910 m3 on a day when the outside air density is 1.22 kg/m3. T
lesya [120]

9514 1404 393

Answer:

  1.114 kg/m³

Explanation:

The total mass of the air in the balloon and the balloon + cargo will be the mass of the displaced air. If d is the density of the air in the balloon, then we have ...

  2910d +308 = 2910×1.22

Solving for d, we find ...

  2910d = 2919(1.22) -308

  d = 1.22 -308/2910

  d ≈ 1.114 . . . kg/m³

The density of the hot air is about 1.114 kg/m³.

6 0
3 years ago
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