Answer:
The osmotic pressure is 8.85 atm
Explanation:
Step : Data given
Mass of glucose = 55.0 grams
Volume of water =800.0 mL
Temperature = 10.0 °C
Step 2: Calculate moles glucose
Moles glucose = mass glucose / molar mass glucose
Moles glucose = 55.0 grams / 180.156 g/mol
Moles glucose = 0.305 moles
Step 3: Calculate osmotic pressure
π = iMRT
⇒ with π = the osmotic pressure = TO BE DETERMINED
⇒ with i = the van't Hoff factor for glucose = 1
⇒ with M = the concentration = moles / volume = 0.305 moles / 0.800 L =0.381 M
⇒ with R = the gas constant = 0.08206 L*atm*mol¨K
⇒ with T = the temperature = 10.0 °C = 283 K
π = 1* 0.381 *0.08206 * 283
π = 8.85 atm
The osmotic pressure is 8.85 atm
