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aalyn [17]
3 years ago
14

How do I find this missing measurement?

Mathematics
2 answers:
Fiesta28 [93]3 years ago
5 0
The area of a parallelogram is equal to the base times the height.

In terms of algebra
A = b*h

We know the base is b = 8.2,the area is A = 65.6, though we don't know the height h. We can use algebra to solve

A = b*h
65.6 = 8.2*h
8.2*h = 65.6
8.2*h/8.2 = 65.6/8.2 <--- divide both sides by 8.2
h = 8

The height of the parallelogram is 8 inches

ser-zykov [4K]3 years ago
3 0
The parellogram is 8 inches
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Point C is located 8 inches from Point A and 6 inches from Point B. Points A and B are 2 inches apart. which statement is true?
jek_recluse [69]
I think Point A and B are 2 inches apart or all of them is right
5 0
3 years ago
What are the coordinates of the x-intercept(s) of the graph of y=(x-6)(x+5)
MissTica

Answer:

(-5 , 0) and (6 , 0)

Step-by-step explanation:

In order to get the coordinates of the x-intercept(s) of the graph of y=(x-6)(x+5)

we need to solve for x the equation (x-6)(x+5) = 0

(x-6)(x+5) = 0

⇌

x - 6 = 0  or  x + 5 = 0

⇌

x = 6  or  x = -5

therefore

the coordinates are :

(-5 , 0) and (6 , 0)

__________________________

:)

3 0
3 years ago
Yassar has purchased a $30,000 car for his business. The car depreciates at 30%
fiasKO [112]

Answer:

A

Step-by-step explanation:

30% of 30000 is 9000, 30000-9000=21000 (1 year)

30% of 21000 is 6300, 21000-6300=14700 (2 years)

30% of 14700 is 4410, 14700-4410= 10290 (3 years)

30% of 10290 is 3087, 10290-3097= 7203 (4 years)

30% of 7203 is 2160.9, 7203-2160.9= 5042.1 (5 years)

5 0
2 years ago
How to use the unit circle to find the value of tan (-180)?
vodomira [7]
The point on the unit circle corresponding to -180 degrees is
 ((x, y) = (-1, 0). 

<span>tan(-180°) = y/x = 0/(-1) = 0</span>
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bn%5E5%7D%7Bn-6%7D%20%2A%20%5Cfrac%7Bn%5E2-6%7D%7Bn%5E8%7D" id="TexFormula1" title="\
ddd [48]

Step-by-step explanation:

Dod you mean

=  \frac{ {n}^{5} }{ {n}^{ - 2} }  \times  \frac{ {n}^{2 - 6} }{ {n}^{8} }

=  {n}^{5 - ( - 2)}  \times  {n}^{2 - 6 - 8}

=  {n}^{7}  \times  {n}^{ - 12}

=  {n}^{7 + ( - 12)}

=  {n}^{ - 5}  =  \frac{1}{ {n}^{5} }

5 0
2 years ago
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