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tensa zangetsu [6.8K]
3 years ago
10

What mass of NaOH is in 3.0e+02 mL of a 5.0 M NaOH solution?

Chemistry
1 answer:
Snezhnost [94]3 years ago
3 0
Answer is: mass of sodium hydroxide is 60 grams.
V(NaOH) = 300 mL · 1 L/1000mL = 0,3 L.
c(NaOH) = 5 M = 5 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 5 mol/L · 0,3 L.
n(NaOH) = 1,5 mol.
m(NaOH) = n(NaOH) · M(NaOH).
m(NaOH) = 1,5 mol · 40 g/mol.
m(NaOH) = 60 g.
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<h3>Further explanation</h3>

Given

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