How many unique 13C NMR signals exist in the spectrum for the following compound?
1 answer:
Answer:
Five signals exist in the spectrum of 4-methylpent-1-ene.
Explanation:
Nuclear Magnetic Resonance (NMR) is the main technique used by Scientists particularly by Chemists to elucidate the structure of compounds mainly organic compounds.
There are different NMR techniques which are used to characterize different NMR active nuclei like ¹H-NMR, ¹³C-NMR, ¹⁵N-NMR, ¹⁹F-NMR e.t.c.
In given case the compound will show five different signal for six carbon atoms. THis is because among the six carbon atoms two of them have same electronic environment means they are having same electron surrounding thus, they will share a signal at same ppm. Hence, the signals and each signal shown by each carbon atom is shown below.
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Answer:
Standard free-energy change at is
Explanation:
Oxidation:
Reduction:
--------------------------------------------------------------------------------------
Overall:
Standard cell potential,
So,
We know, standard free energy change at (
):
where, n is number of electron exchanged during cell reaction, 1F equal to 96500 C/mol
Here n = 2
So,
Answer:
1) 1,1,1-trichloropropane
2) 1,1,2-trichloropropane
3) 1,2,2-trichloropropane
4) 1,2,3-trichloropropane
Explanation:
For this question, we must remember that isomers are molecules that have the <em>same formula but different structure</em>s. For the formula we can draw a <u>linear chain of three carbons</u> and change the position of the chlorine atoms in the carbon chain.
With this in mind, if we put all the chlorine atoms on the same carbon we will get <u>1,1,1-trichloropropane</u>. If we change an atom from chlorine to carbon 2 we will obtain <u>1,1,2-trichloropropane</u>. If we move another chlorine atom to carbon two we will get <u>1,2,2-trichloropropane</u>. Finally, if we put a chlorine atom in each carbon we will obtain <u>1,2,3-trichloropropane</u>.
See figure one for further explanations
I hope it helps!
