Answer:
C6H12O6
Explanation:
I attached the method for solving above.
How many unique 13C NMR signals exist in the spectrum for the following compound?
1 answer:
Answer:
Five signals exist in the spectrum of 4-methylpent-1-ene.
Explanation:
Nuclear Magnetic Resonance (NMR) is the main technique used by Scientists particularly by Chemists to elucidate the structure of compounds mainly organic compounds.
There are different NMR techniques which are used to characterize different NMR active nuclei like ¹H-NMR, ¹³C-NMR, ¹⁵N-NMR, ¹⁹F-NMR e.t.c.
In given case the compound will show five different signal for six carbon atoms. THis is because among the six carbon atoms two of them have same electronic environment means they are having same electron surrounding thus, they will share a signal at same ppm. Hence, the signals and each signal shown by each carbon atom is shown below.
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Answer: The statement which could possibly not be true is C -" Liquid X can exist as a stable phase at 25°C, 1atm."
Explanation:
Triple point is the point where a substance co-exist as solid liquid and gas. At any point other than the triple point, the substance exist as a single phase substance.
As shown in the diagram, Liquid cannot exist as a stable phase at 1atm( below the the triple point pressure of 2atm) as the liquid can only exist beyond the pressure of triple point.
Answer:
Explanation:
- State of benzene at RTP = liquid
- State of chloroform at RTP = liquid
- Boiling point of benzene = 80.1 °C
- Boiling point of chloroform = 61.2 °C
Since, both of the chemicals are liquids, we can separate it by the process of distillation.
<u>Distillation:</u>
- is the process in which we separate two liquids on the basis of their difference in boiling points.
<u>How it works:</u>
Since chloroform has less boiling point, it will evaporate and collected first and benzene will follow it after sometime.
- Apparatus of distillation is in the attached file.
