The answer is 10.5 kg m/s
Impulse (I) is the multiplication of force (F) and time interval (Δt): I = F · Δt
Force (F) is the multiplication of mass (m) and acceleration (a): F = m · a
Acceleration (a) can be expressed as change in velocity (v) divided by time interval (Δt): a = Δv/Δt
So:
a = Δv/Δt ⇒ F = m · a = m · Δv/Δt
F = m · Δv/Δt ⇒ I = m · Δv/Δt · Δt
Since Δt can be cancelled out, impulse can be expressed as:
I = m · Δv = m · (v2 - v1)
It is given:
m = 1.5 kg
v1 = 15 m/s
v2 = 22 m/s
I = 1.5 · (22 - 15) = 1.5 · 7 = 10.5 kgm/s.
Answer:
255.4 N/m
Explanation:
We can consider the system eyeball-attached to the musculature as a mass-spring system in simple harmonic motion, whose frequency of oscillation is given by
where in this case, we know:
f = 29 Hz is the frequency of oscillation
k is the spring constant, which is unknown
m = 7.7 g = 0.0077 kg is the mass of the eyeball
Solving the equation for k, we find the spring constant of the musculature attached to the eyeball:
I think it’s the third one, if not it’s the first.
The answer should be ''Decrease'' to fill in the blank because squirrels usually live in trees and get food from there so without a place to live when its raining and no food to survive, than they would die and lessen their population so that's why decrease is the answer.
