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andrew11 [14]
2 years ago
9

A model shows a machine that works using electric fields. What would this machine need for the electrical field to function prop

erly
Physics
1 answer:
Wittaler [7]2 years ago
7 0
It would need at least two charges interacting parts
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levacccp [35]
2. random motion in vertical direction
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3 years ago
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Why do atoms have an overall neutral charge?
Y_Kistochka [10]
Atoms have an overall charge that is neutral because atoms have equal number of positive protons and negative electrons thus they cancel each other out. This always true for atoms that are stable and in equilibrium.
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3 years ago
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High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45
almond37 [142]

Answer:

The speed will be "1.06 m/s".

Explanation:

The given values are:

Momentum,

m1 = 244 g

m2 = 45.2 g

On applying momentum conservation ,

Let v2 become the final golf's speed.  

From Momentum Conservation

⇒  Total \ initial \ momentum = Total \ final \ momentum

⇒  m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2

On putting the estimated values, we get

⇒  0.244\times 57.6+0=0.244\times 39.9+45.2\times v2

⇒  57.844+0=9.7356+45.2\times v2

⇒  48.1084=45.2\times v2

⇒  v2=\frac{48.1084}{45.2}

⇒  v2=1.06 \ m/s

6 0
3 years ago
A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. What is the approxi
Alja [10]
The approximate acceleration of the car would be <span>3.00

</span>How? We have to use the formula to find the velocity.

v = d/t = 120/6.32

v = 19

Then plug the factor into the acceleration formula to find the acceleration:

a = v/t = 19/6.32

a = 3.00

So, the approximate acceleration of the car would be 3.00
4 0
4 years ago
A 0.3 g mosquito is flying toward a girl with a speed of 4.5 mph. Just before landing on the girl, the fly is swatted straight b
luda_lava [24]

Answer:

1.1x10^-2N

Explanation:

We have the change in momentum as

P = 0.3(4.5+12)g.mph

= 0.3x0.447x(4.5+12)x10^-3

Then the force that is exerted will be

F = p/∆t

∆t = 0.2

= 0.3x0.447x(4.5+12)x10^-3/0.2

= 0.1341x16.5x10^-3/0.2

= 1.1x10^-2

Therefore the force that was exerted is equal to 1.1x10^-2

5 0
3 years ago
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