Answer:
4589.05 year
Explanation:
The relation of activity is given by 
we have given 
Half life 
We know that half life 
So 
D. Yuri Gagarin
(Typing this to circumnavigate the 20 character minimum requirement)
Answer:
a. before
Explanation:
Did the displacement at this point reach its maximum of 2 mm before or after the interval of time when the displacement was a constant 1 mm?
from the graph given from a source. the vertical axis represents the displacement of the graph motion, whilst the horizontal side is representing the time variable of the motion .
displacement is distance in a specific direction.
before the displacement was maximum at 2mm was instant at time=0.04s.
But later was constant at 0.06s at a displacement point of 1mm
Answer:
a2 = 2.5 m/s2
Explanation:
F1 = m1 a1 We use the same force so F1 = F2
= 5kg × 15m/s2 F2 = m2 a2
= 75N a2 is required
a2 = F2 / m2
= 75N / 30 kg
= 2.5 m/s2
Answer:
366 K
Explanation:
T₀ = Constant Temperature of deep lake = 293.0 K
T = Temperature of hot reservoir connected to carnot engine = ?
η = Efficiency of Carnot engine during the operation
Efficiency of Carnot engine is given as
Inserting the values
T = 366 K
