To solve this problem we will apply the theorem given in the conservation of energy, by which we have that it is conserved and that in terms of potential and kinetic energy, in their initial moment they must be equal to the final potential and kinetic energy. This is,
Replacing the 5100MJ for satellite as initial potential energy, 4200MJ for initial kinetic energy and 5700MJ for final potential energy we have that
Therefore the final kinetic energy is 3600MJ
Answer:
Acceleration of the bags is 0.861 m/s²
Explanation:
Given:
Mass of the rock, m = 22.5 kg = mass of the food
Slope, Θ = 55.5°
Now, from the figure, we have
T - mgsinΘ = ma ...................(1)
'a' is the acceleration of the mass
where T is the tension
also for the second mass, we have
mg - T = ma
now substituting the value of T from the equation (1) we get
mg - (ma + mgsinΘ) = ma
or
mg(1 - sinΘ) = (m + m)a
or
a =
on substituting the values we get
a =
or
a = 0.861 m/s²
Hence, the acceleration of the bags is 0.861 m/s²
Answer:
0.01774 lux
Explanation:
= Polarized light intensity = 36.8 lux
= Angle
Through first filter
Through second filter
intensity of transmitted light is 0.01774 lux