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masya89 [10]
3 years ago
8

A Carnot heat engine has an efficiency of 0.200. If it operates between a deep lake with a constant temperature of 293.0 K and a

hot reservoir, what is the temperature of the hot reservoir? O 352 K O 1760 K O 366 K 1470 K
Physics
1 answer:
Dimas [21]3 years ago
3 0

Answer:

366 K

Explanation:

T₀ = Constant Temperature of deep lake = 293.0 K

T = Temperature of hot reservoir  connected to carnot engine = ?

η = Efficiency of Carnot engine during the operation

Efficiency of Carnot engine is given as

\eta = 1-\frac{T_{o}}{T}

Inserting the values

0.200 = 1-\frac{293.0}{T}

T = 366 K

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Answer:

a) v=0.999124c

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c) E_a=760 times\ larger

Explanation:

From the question we are told that

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b)

Generally the equation of the energy E required to attain prior speed mathematically given by

E=\frac{1}{\sqrt{1-(v/c)^2} }-1(20000kg)(3*10^8m/s)^2

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c)Generally the equation of the energy E_a required to accelerate the rocket mathematically given by

E_a=\frac{E}{E_{2000}}

E_a=\frac{7.566*10^{22}}{1.0*10^{20}}

E_a=760 times\ larger

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Answer:

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