Answer:
True
Explanation:
Gauss's law:
It is one of the Maxwell's equations which are the foundation of Electrodynamics. According to this law magnetic field has zero divergence and magnetic monopole can't exist. Inside a closed surface, the magnetic flux inward at the south pole will be exactly equal to the outward magnetic flux at the north pole of the magnetic dipole. Thus, the net magnetic flux will be zero.
Elliptical galaxies are galaxies that are shaped like an ellipse. An ellipse is oval in shape, which means elliptical galaxies are oval in shape.
The <u>two correct statements</u> that describe elliptical galaxies are:
B. They are the most common galaxy type.
C. They typically contain very little gas and dust.
- Elliptical galaxies are galaxies where you will find little or no gas and dust. The galaxies that are numerous in number are the elliptical galaxies.
- In the elliptical galaxy, you can't find any <u>spiral component </u>in it.
Therefore, from the above explanation, we can see that <u>option B and C is the correct option.</u>
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Answer:
So electric field between the plates will be equal to 
Explanation:
We have given potential difference between accelerating plates = 24 KV = 24000 volt
Distance between the plates d = 1.5 cm = 0.015 m
We know that potential difference is given by V = Ed, here E is electric field and d is distance between plates
So 
E = 1600000 N/C = 
So electric field between plates will be equal to 
The equilibrium temperature is T13=3.12 ◦C
<u>Explanation:</u>
<u>Given </u>
The temperature of liquids: T1=6◦C, T2=23◦C, T3=38◦C
The temperature of 1+2 liquids mix: T12= 13◦C.
The temperature of 2+3 liquids mix: T23=26.8 ◦C.
The temperature of 1+3 liquids mix: T13= ??
<u>1.When the first two liquids are mixed:</u>
- mC1(T1-T12)+mC2(T2-T12)=0
- C1(6-13)=C2(23-13)=0
- 7C1=10C2
- C1=1.42C2
<u>2.When the second and third liquids are mixed</u><u>:</u>
- mC2(T2-T23)+mC3(T3-T23)=0
- C2(23-26.8)=C3(38-26.8)=0
- 3.8C2=12.8C3
- C2=3.36C3
<u>3.When the first and third liquids are mixed:</u>
- mC1(T1-T13)+mC3(T3-T13)=0
- C1(6-T13)+C3(38-T13)=0
- C1=1.42C2 C2=3.36C3
- C1=1.42C2(3.36C3)
- C1=4.77C3
- C1(6-T13)+C3(38-T13)=0
- 4.77C3(6-T13)+C3(38-T13)=0
- By solving the equation we get,
- T13=3.12 ◦C
- The equilibrium temperature is T13=3.12 ◦C
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It is called weathering. there are three different types of weathering, physical weathering, chemical weathering, and biological weathering. Your particular question is caused by chemical weathering.