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Sergeeva-Olga [200]
3 years ago
11

You need to make an aqueous solution of 0.192 M barium sulfide for an experiment in lab, using a 500 mL volumetric flask. How mu

ch solid barium sulfide should you add?
Chemistry
1 answer:
shutvik [7]3 years ago
7 0

Answer:

Explanation:

Molecular weight of barium sulphide = 169

500 mL of .192 M barium sulfide = .5 x .192 moles of barium sulphide

= .096 moles of barium sulfide

= .096 x 169 gram of barium sulfide

= 16.22 grams of barium sulfide .

We shall have to add 16.22 gram .

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The angular momentum quantum number for the outermost electrons in a phosphorus atom in the ground state is __________.
fredd [130]

Answer:

l=1

Explanation:

The angular momentum quantum number is a quantum number that describes the 'shape' of an orbital and tells us which subshells are present in the principal shell. A critical look at the electronic configuration of phosphorus at the ground state depicts the outermost electron to be in the P orbital where the angular quantum number ,l=1 .

8 0
4 years ago
Which one of the following is an example of a difficulty caused by thermal
Sladkaya [172]

Answer: A

Explanation:just passed it

5 0
3 years ago
The hormone, thyroxine is secreted by the thyroid gland, and has the formula: c15h17no4i4. How many milligrams of iodine can be
Mandarinka [93]

Answer:

9.73 grams of iodine

Explanation:

First we calculate the molar mass of the tyroxine C₁₅H₁₇NO₄I₄:

M = 15 × 12 + 17 × 1 + 1 × 14 + 4 × 16 + 4 × 127 = 783 g/mole

The taking in account that 1 mole of tyroxine have 4 moles of iodine atoms (508 g) we devise the following reasoning:

if from   783 g of tyroxine we can extract 508 g of iodine

the from  15 g of tyroxine we can extract X g of iodine

X = (15 × 508) / 783 = 9.73 grams of iodine

4 0
4 years ago
Which of these actions would increase heat transfer between two objects?
kicyunya [14]
I believe it would be the 2nd one, “increasing the area of their contact”.
8 0
3 years ago
Read 2 more answers
SOMEONE help! due today <br> 25 POINTS<br> SEE ATTACHED.
Llana [10]

Answer:

Q4. 2H₂ + O₂ ⟶ 2H₂O; 5; 2

Q5. 24; 30; H₂; 0; 5

Explanation:

Q4.

The equation for the reaction is

2H₂ + O₂ ⟶ 2H₂O

One O₂ molecule reacts with 2H₂ molecules.

\text{No. of O$_{2}$ molecules} = \text{10 H$_{2}$ molecules } \times \dfrac{\text{1 O$_{2}$ molecule }}{\text{2 H$_{2}$ molecules}} = \textbf{5 O$_{\textbf{2}}$ molecules}\\\\\text{Ten hydrogen molecules react with $\textbf{five}$ oxygen molecules.}

We started with seven oxygen molecules. Five of them reacted, so

Two O₂ molecules did not react.

Q5.

Two water molecules form from two hydrogen molecules.

\text{No. of H$_{2}$O molecules} = \text{24 H$_{2}$ molecules } \times \dfrac{\text{2 H$_{2}$O molecules}}{\text{2 H$_{2}$ molecules}} = \textbf{24 H$_{\textbf{2}}$O molecules}Two water molecules form from one oxygen molecule

\text{No. of H$_{2}$O molecules} = \text{15 O$_{2}$ molecules } \times \dfrac{\text{2 H$_{2}$O molecules}}{\text{1 O$_{2}$ molecules}} = \textbf{30 H$_{\textbf{2}}$O molecules}Hydrogen forms fewer water molecules of water, so

Hydrogen is the limiting reactant.

The 24 hydrogen molecules will be completely used up.

The number of hydrogen molecules remaining at the end of the reaction is zero.

They have reacted with 12 O₂ molecules.

The number of O₂ molecules remaining is 17 - 12 = 5

5 0
3 years ago
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