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2 years ago

If a solution turns litmus paper turns red, which type of solution is it?

Chemistry

1 answer:

kari74 [83]2 years ago

5 0

It is a base due to the color change!

Hope this helps!

Mark me brainliest please...

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The standard unit (SI) for mass is

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The kilogram is the si

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3 years ago

What is the product if an atom of Po-209<br> undergoes alpha decay?

g100num [7]

<h3>Answer:</h3>

Lead-205 (Pb-205)

<h3>Explanation:</h3>

<u>We are given;</u>

An atom of Po-209

We are supposed to identify its product after an alpha decay;

Polonium-209 has a mass number of 209 and an atomic number of 84.
When an element undergoes an alpha decay, the mass number decreases by 4 while the atomic number decreases by 2.
Therefore, when Po-209 undergoes alpha decay it results to the formation of a product with a mass number of 205 and atomic number of 82.
The product from this decay is Pb-205, because Pb-205 has a mass number of 205 and atomic number 82.

The equation for the decay is;

²⁰⁹₈₄Po → ²⁰⁵₈₂Pb + ⁴₂He

Note; An alpha particle is represented by a helium nucleus, ⁴₂He.

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3 years ago

A sample of oxygen gas has a volume of 150.0 ml when its pressure is .947 atm. what will the volume of the gas be if the tempera

joja [24]

D
Hope it helped you get an A, Kayla.

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2 years ago

Alguien sabe el nombre del compuesto etilisopropilacetileno?

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3 years ago

9. If 28.56 g of K2O is produced when 25.00 g K is reactedaccording to the following equation, what is the percent yieldof the r

Mumz [18]

Answer

b. 95%

Explanation

Given:

Mass of K₂O produced (actual yield) = 28.56 g

Mass of K that reacted = 25.00 g

Equation: 4K(s) + O₂(g) → 2K₂0(s)

What to find:

The percent yield of K₂O.

Step-by-step solution:

The first step is to calculate the theoretical yield of K₂O produced.

From the balanced equation, 4 mol K produced 2 mol K₂O

Molar mass of K₂O = 94.20 g/mol)

Molar mass of K = 39.10 g/mol)

This means 4 mol x 39.10 g/mol = 156.40 g K produced 2 mol x 94.20 g/mol = 188.40 g K₂O

So 25.00 g K will produce:

$\frac{25.00\text{ }g\text{ }K\times188.40\text{ }g\text{ }K₂O}{156.40\text{ }g\text{ }K}=30.1151\text{ }g\text{ }K₂O$

Actual yield of K₂O = 28.56 g

Theoretical yield of k₂O = 30.1151 g

The percent yield for the reaction can now be calculated using the formula below:

$\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\% \\ \\ Percent\text{ }yield=\frac{28.56\text{ }g}{30.1151\text{ }g}\times100\% \\ \\ Percent\text{ }yield=0.9484\times100\% \\ \\ Percent\text{ }yield=94.84\%\approx95\% \end{gathered}$

Therefore, the percent yield for the reaction is 95%.

3 0

1 year ago