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romanna [79]
3 years ago
7

A Geometric series has a first term of 4 and a common ratio of 6. what formula is equivalent to the partial sum of the first n t

erms of the series.
Mathematics
1 answer:
IRISSAK [1]3 years ago
6 0
\bf \qquad \qquad \textit{sum of a finite geometric sequence}
\\\\
S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
a_1=4\\
r=6
\end{cases}
\\\\\\
S_n=4\left( \cfrac{1-6^n}{1-6} \right)\implies S_n=4\left( \cfrac{1-6^n}{-5} \right)
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Hope this answer helps you! If it did, please mark it as the brainiest! I would really appreciate it! :)

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polet [3.4K]

Answer:

<h2>210 cm³</h2>

Step-by-step explanation:

let V represent the volume of the triangular prism

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base = (7×6)/2 = 42/2 = 21

height = 10

then

V = 21×10 = 210

7 0
3 years ago
What is a quotient of 2.5.
Arlecino [84]

Answer:

The quotient is the solution to a division sum.

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4 0
3 years ago
Assume that the notation (a,r,s,t) means multiply q and r, then add the product to s and (2,6,4,8)+(4,7,2,6)? Please show work a
Mama L [17]
<h3>Answer:  7.0   (choice E)</h3>

=============================================

Work Shown:

\perp (q,r,s,t) = \frac{qr + s}{t}\\\\\perp (2,6,4,8) = \frac{2*6 + 4}{8}\\\\\perp (2,6,4,8) = \frac{12 + 4}{8}\\\\\perp (2,6,4,8) = \frac{16}{8}\\\\\perp (2,6,4,8) = 2\\\\

Let m = 2 so we can use this result later.

\perp (q,r,s,t) = \frac{qr + s}{t}\\\\\perp (4,7,2,6) = \frac{4*7 + 2}{6}\\\\\perp (4,7,2,6) = \frac{28 + 2}{6}\\\\\perp (4,7,2,6) = \frac{30}{6}\\\\\perp (4,7,2,6) = 5\\\\

Let n = 5 so we can use this result later.

Add the two results.

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5 0
2 years ago
. You work at a department store and make $9 per hour plus 12% commission
Luda [366]
Start with hours worked 6 x $9 = 54
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So answers are A, the first C (you make $84 in commission), and the last one, you make $138 in total.
5 0
3 years ago
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