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Tom [10]
3 years ago
15

Why sky appear blue ​

Physics
1 answer:
NikAS [45]3 years ago
5 0
Thus, as sunlight of all colors passes through air, the blue part causes charged particles to oscillate faster than does the red part. ... More of the sunlight entering the atmosphere is blue than violet, however, and our eyes are somewhat more sensitive to blue light than to violet light, so the sky appears blue.Apr 7, 2003
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In the following diagram, the voltage is 1.5 volts and the resistance is 3.0 ohms. Use Ohm's law to determine the current in the
photoshop1234 [79]

Current = Voltage/Resistance

             = 1.5/3

Current = 0.5 amps - A

3 0
3 years ago
Read 2 more answers
Tectonic plates are large segments of the earth's crust that move slowly. Suppose one such plate has an average speed of 6.0 cm
faltersainse [42]

Answer:

1.35×10⁻⁷ m

37.278 mi/My

Explanation:

Speed of the tectonic plate= 6 cm/yr

Converting to seconds

6=\frac{6}{365.25\times 24\times 60\times 60}

So in one second it will move

\frac{6}{365.25\times 24\times 60\times 60}

In 71 seconds

71\times \frac{6}{365.25\times 24\times 60\times 60}=1.35\times 10^{-5}\ cm

The tectonic plate will move 1.35×10⁻⁵ cm or 1.35×10⁻⁷ m

Convert to mi/My

1 cm = 6.213×10⁻⁶ mi

1 M = 10⁶ years

6\times 6.213\times 10^{-6}\times 10^6=37.278\ mi/My

Speed of the tectonic plate is 37.278 mi/My

7 0
3 years ago
a projectile is fired in such away that its horizontal range is equal to three times its naximum height.what is the angle of pro
finlep [7]

Answer:

\theta=53.13^o

Explanation:

<u>2-D Projectile Motion</u>

In 2-D motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration, while the acceleration in the vertical direction is always the acceleration due to gravity. The basic formulas for this type of movement are

V_x=V_{ox}=V_ocos\theta

V_y=V_{oy}-gt=V_osin\theta-gt

x=V_{ox}t

\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}

\displaystyle x_{max}=\frac{2V_{ox}V_{oy}}{g}

\displaystyle y_{max}=\frac{V_{oy}^2}{2g}

The projectile is fired in such a way that its horizontal range is equal to three times its maximum height. We need to find the angle \theta at which the object should be launched. The range is the maximum horizontal distance reached by the projectile, so we establish the base condition:

x_{max}=3y_{max}

\displaystyle \frac{2V_{ox}V_{oy}}{g}=3\frac{V_{oy}^2}{2g}

Using the formulas for V_{ox}, V_{oy}:

\displaystyle \frac{2V_{o}cos\theta V_{o}sin\theta}{g}=3\frac{V_{o}^2sin^2\theta}{2g}

Simplifying

4cos\theta sin\theta=3sin^2\theta

Dividing by sin\theta

4cos\theta=3sin\theta

Rearranging

tan\theta=\frac{4}{3}

\theta=arctan\frac{4}{3}

\theta=53.13^o

4 0
3 years ago
A 45.2 kg softball player slides across dirt with Uk=0.340. What is her acceleration?
alisha [4.7K]

Answer:

the ball didnt hit my face so

Explanation:

8 0
3 years ago
What advantage do space telescopes have over telescopes used on earth?
Elina [12.6K]
Earth's atmosphere blocks many types of light including gamma, x-rays most ultraviolet and infrared. So optical telescopes that use visible light and ultraviolet telescopes that are used to study very hot stars are much less effective on Earth.
4 0
3 years ago
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