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Fittoniya [83]
3 years ago
7

A vertical piston-cylinder device contains water and is being heated on top of a range. During the process, 63 Btu of heat is tr

ansferred to the water, and heat losses from the side walls amount to 8 Btu. The piston rises as a result of evaporation, and 5 Btu of work is done by the vapor. Determine the change in the energy of the water for this process
Physics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

The water would have a change in the energy of 50 BTU

Explanation:

  1. Under the assumption that the piston-cylinder system is a closed system, then the conservation law of the system would be: E_{in}-E_{out}=E_{change}, where E_{in} is all the energy that goes into the system, E_{out} is all the energy that leaves the system and, E_{change} is the change of the energy of the system.
  2. For this case the energy that is feeded to the system is heat: 63 BTU.
  3. There is two ways that energy is leaving this system: 8 BTU of heat as losses through the side walls and, 5 BTU of work done by the vapor on the piston.
  4. Then the change of energy of the system is: E_{change}=E_{in}-E_{out}=63 BTU-(8BTU+5BTU)=50BTU.
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lisabon 2012 [21]

Sustainable buildings are generally less expensive over the lifetime of the building, due to lower energy costs in production of the materials and lower energy bills. Option A is correct.

<h3>What is sustainable buildings? </h3>

Sustainable buildings refer to both a structure and the implementation of environmentally responsible and resource-efficient methods.

Sustainable buildings are generally less expensive over the lifetime of the building, due to lower energy costs in production of the materials and lower energy bills,

Hence,option A is correct.

To learn more about the sustainable buildings, refer;

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5 0
2 years ago
Ediment deposited where a river flows into an ocean or lake
Triss [41]
The answer is Delta.
3 0
3 years ago
Equipotentials are lines along which Select one: a. the electric field is constant in magnitude and direction. b. the electric c
soldi70 [24.7K]

Answer:

option D is correct

Explanation:

It is important to note that equipotential lines are always perpendicular to electric field lines. No work is required to move a charge along an equipotential, since ΔV = 0. Thus the work is :

                                W = −ΔPE = −qΔV = 0.

Work is zero if force is perpendicular to motion. Force is in the same direction as E, so that motion along an equipotential must be perpendicular to E. More precisely, work is related to the electric field by:

                                 W = Fd cos θ = qEd cos θ = 0.

- The change in kinetic energy Δ K.E by conservation should be:

                                 Δ K.E = W

Since, W = 0:

                                Δ K.E = 0

- If change in kinetic energy is zero it means that charge moves at a constant speed. Hence, option D is correct.

4 0
3 years ago
A clown balances a small spherical grape at the top of his bald head, which also has the shape of a sphere. After drawing suffic
prisoha [69]
<h2>Answer:</h2>

<em><u>48.189°</u></em>

<h2>Explanation:</h2>

Let us say,

Radius of curvature of the clown's bald head is = R

Angle where the grape leaves the contact with the head is (with vertical) = θ

Height from the top of the head at which the contact is lost = y

Mass of the grape = m

Velocity of the grape at the point where it loses contact = v

So,

Using the <u>Conservation of Work and Energy,</u> we can say that there is 0 Work done on the system,

W = ΔK + ΔU

So,

0=(\frac{1}{2}mv^{2}-0)+(mgy-0)\\v^{2}=2gy\\Now,\\y=R-Rcos\theta\\y=R(1-cos\theta)\\So,\\v^{2}=2[R(1-cos\theta)]g

Now, using this at the point where contact is lost,

N=-m(\frac{v^{2}}{R})+mg.cos\theta\\N=-m[2g(1-cos\theta)]+mg.cos\theta\\

At that point the <u>Normal force will be zero, because the contact is lost.</u>

So,

On putting, N = 0 we get,

N=-m[2g(1-cos\theta)]+mg.cos\theta\\0=-m[2g(1-cos\theta)]+mg.cos\theta\\2g-2g.cos\theta=g.cos\theta\\3g.cos\theta=2g\\cos\theta=\frac{2}{3}\\\theta=48.189\,degrees

<em><u>Therefore, the angle at which the grape lose contact with the bald head is at 48.189° from vertical.</u></em>

7 0
3 years ago
What is the magnitude and direction of an electric field that exerts a 2.00 * 10^-5 N upward force on a −1.5 μC charge?
Over [174]

The relation between electric field intensity, electric force and charge is given as follow,

E = \frac{F}{q}

Where,

F = Force

q = Charge

The direction of force on a charge placed in an electric field is same as the direction of electric field if the charge has positive polarity and opposite if charge has negative polarity.

Replacing we have that

E = \frac{2*10^{-5}N}{-1.5*10^{-6}C}

E = -13.3N/C

As direction of force is upward and polarity of charge is negative, hence the direction of field will be opposite to that of force. Therefore direction of field is downward.

4 0
4 years ago
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