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Fittoniya [83]
3 years ago
7

A vertical piston-cylinder device contains water and is being heated on top of a range. During the process, 63 Btu of heat is tr

ansferred to the water, and heat losses from the side walls amount to 8 Btu. The piston rises as a result of evaporation, and 5 Btu of work is done by the vapor. Determine the change in the energy of the water for this process
Physics
1 answer:
jolli1 [7]3 years ago
6 0

Answer:

The water would have a change in the energy of 50 BTU

Explanation:

  1. Under the assumption that the piston-cylinder system is a closed system, then the conservation law of the system would be: E_{in}-E_{out}=E_{change}, where E_{in} is all the energy that goes into the system, E_{out} is all the energy that leaves the system and, E_{change} is the change of the energy of the system.
  2. For this case the energy that is feeded to the system is heat: 63 BTU.
  3. There is two ways that energy is leaving this system: 8 BTU of heat as losses through the side walls and, 5 BTU of work done by the vapor on the piston.
  4. Then the change of energy of the system is: E_{change}=E_{in}-E_{out}=63 BTU-(8BTU+5BTU)=50BTU.
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Explanation:

Work done by gravity is given by the formula,

           W = \rho A (h_{1} - h)g (h - h_{2}) ......... (1)

It is known that when levels are same then height of the liquid is as follows.

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Putting value of equation (2) in equation (1) the overall formula will be as follows.

       W = \frac{1}{4} \rho gA(h_{1} - h_{2})^{2})

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