Answer:
1.78
Explanation:
1mole produce 18g/x will produce 32g then the answer is 1.78moles
Answer:
In full volume it contain 0.12 moles.
Explanation:
Given data:
Total volume= Vt = 2.9 L
Decreased volume= Vd = 1.2 L
Number of moles of air present in decreased volume= n = 0.049 mol
Number of moles of air in total volume= n = ?
Solution:
Formula:
Vt/ Vd = n (in total volume) /n ( decreased volume)
2.9 L / 1.2 L = X / 0.049 mol
2.42 = X / 0.049 mol
X = 2.42 × 0.049
X = 0.12 mol
Answer:
b
. 0.351 L.
Explanation:
Hello!
In this case, since diluted solutions are prepared by adding an extra amount of diluent to a stock-concentrated solution, we infer that the number of moles of solute remains the same, therefore we can write:
Thus, solving for the volume of the stock solution, V1, we obtain:
Now, by plugging in the given data we obtain:
Therefore, the answer is b
. 0.351 L.
Best regards!
For for the formulas with the abbreviated names of the ions, you switch the exponents for each one, so for number 2 it would be Fe2O3 or for 6 it would be CaCl2
For the compounds, you take the abbreviated names of the ions from the periodic table and wherever the ion falls, that’s how many electrons it has and so it would need more ions to make the full shell, so for sodium chloride, since both need one, it would be NaCl or for tin (ll) fluoride, it would be SnF2
<h3>
Answer:</h3>
The higher is its frequency.
<h3>
Explanation:</h3>
- Electromagnetic waves are types of waves that do not require a material medium for transmission.
- They include radio waves, microwaves, infra-red and gamma rays among others.
- Frequency refers to the number of complete oscillations in one second while wavelength is the distance between two successive crests or trough in a transverse wave.
- The frequency of electromagnetic waves varies inversely to the wavelength.
- Electromagnetic waves with higher frequencies such as x-rays and gamma rays have lower wavelengths.
- Those with higher wavelengths, on the other hand, such as microwaves and radio waves have lower frequencies.
