The balanced chemical reaction is written as:
MnCl2(s)+H2SO4(aq)→MnSO4(aq)+2HCl(g)
We are given the amount of hydrochloric acid to be produced in the reaction. This value will be the starting point for the calculations.We do as follows:
.0525 L HCl ( 1 mol / 22.4 L ) ( 1 mol MnCl2 / 2 mol HCl ) (125.84 g / 1 mol ) = 0.15 g MnCl2
Answer: 2.54g
Explanation:
Molar Mass of H2O2 = (2x1) + (2x16) = 34g/mol
1mole (34g) of H2O2 contains 6.02x10^23 molecules
Therefore Xg of H2O2 will contain 4.5x10^22 molecules i.e
Xg of H2O2 = (34x4.5x10^22)/6.02x10^23 = 2.54g
Answer:
19.9 mol
Explanation:
Use <em>Avogadro’s number</em> to convert formula units of CaI₂ to moles of CaI₂.
1 mol CaI₂ ≡ 6.022 × 10²³ formula units CaI₂
Moles of CaI₂ = 1.20 × 10²⁵ × (1 /6.022 × 10²³)
Moles of CaI₂ = 19.9 mol
Answer:
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