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3 years ago

How much 2.0 M NH4NO3 is needed to make 0.585 L of 1.2 M NH4NO3 solution?

Chemistry

1 answer:

Nutka1998 [239]3 years ago

5 0

Answer:

b . 0.351 L.

Explanation:

Hello!

In this case, since diluted solutions are prepared by adding an extra amount of diluent to a stock-concentrated solution, we infer that the number of moles of solute remains the same, therefore we can write:

$C_1V_1=C_2V_2$

Thus, solving for the volume of the stock solution, V1, we obtain:

$V_1=\frac{C_2V_2}{C_1}$

Now, by plugging in the given data we obtain:

$V_1=\frac{1.2M*0.585L}{2.0M}\\\\V_1=0.351L$

Therefore, the answer is b . 0.351 L.

Best regards!

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.7 liters of CO represents how many molecules?

Ronch [10]

Answer:

1.88 × 10²² Molecules of CO

Explanation:

At STP for an ideal gas,

Volume = Mole × 22.4 L/mol

Or,

Mole = Volume / 22.4 L/mol

Mole = 0.7 L / 22.4 L/mol

Mole = 0.03125 moles

Now,

No. of Molecules = Moles × 6.022 × 10²³ Molecules/mol

No. of Molecules = 0.03125 × 6.022 × 10²³ Molecules/mol

No. of Molecules = 1.88 × 10²² Molecules of CO

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2 years ago

Draw the structures of the 3 isomers of C8H18 that contain 3 methyl branches on the main chain, 2 of which are on the same carbo

Vlad1618 [11]

Answer:

Please see the attachments

Explanation:

Please see the attachments below structures of the 3 isomers of C8H18 that contain 3 methyl branches on the main chain, 2 of which are on the same carbon.

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3 years ago

How many moles are in 400.0 g of ammonium sulfide?

sdas [7]

Answer:

This is the exact answer. Please give brainliest. The answer is 132.13952.

Explanation:

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2 years ago

Calculate the amount of heat needed to boil 64.7 g of benzene (C6H6), beginning from a temperature of 41.9 C . Round your answer

JulsSmile [24]

Answer: The amount of heat needed is = 4.3kJ

Explanation:

Amount of heat H = M × C × ΔT

M= mass of benzene = 64.7g

C= specific heat capacity = 1.74J/gK

ΔT = T2-T1

Where T1 is initai temperature = 41.9C

T2 is the final temperature( boiling point of benzene) = 80.1C

H= 64.7×1.74×80.7

H= 4300J

H=4.3kJ

Therefore, the amount of heat needed is 4.3kJ

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3 years ago

An air tight freezer measures 4 mx 5 m x 2.5 m high. With the door open, it fills with 22 °C air at 1 atm pressure.

____ [38]

Answer:

(a) Density of the air = 1.204 kg/m3

(b) Pressure = 93772 Pa or 0.703 mmHg

Explanation:

(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

$\rho_{air}=\frac{P}{R*T}$

First, we change the units of P to Pa and T to deg K:

$P=1 atm * \frac{101,325Pa}{1atm}=101,325 Pa\\\\ T=22+273.15=293.15^{\circ}K$

Then we have

$\rho_{air}=\frac{P}{R*T}=\frac{101325Pa}{287.05 J/(kg*K)*293.15K} =1.204 \frac{kg}{m3}$

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

$PV=nRT\\P/T=nR/V=constant\Rightarrow P_{1}/T_{1}=P_{2}/T_{2}\\\\P_{2}=P_{1}*\frac{T_{2}}{T_{1}}=101325Pa*\frac{7+273.15}{22+273.15}=101,325Pa*0.9254=93,772Pa\\\\P2=93,772 Pa*\frac{1mmHg}{133,322Pa}= 0.703 mmHg$

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

$F=S_{door}*\Delta P=2m^{2} *(101325Pa - 93772Pa)=2m^{2} *7553N/m2=15106N$

7 0

3 years ago