I have a question about this program what are the gold crowns and how do you earn them?

1 answer:

5 0

Gold crowns are earned by answering peoples questions and them giving you 'The brainliest answer'. There is no solid way of getting gold crowns as they are awarded by the person presenting a question. The best advice I can give you for getting them is by providing the best and most explained and well thought out correct answer to peoples questions.

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which number is equivalent to 3 to the 4th power over 3 to the 2nd power (its a fraction thats why i said over)

Westkost [7]

So you know that 3^4 is your numerator and that is (4)(4)(4)(4)=81
3^2 is your denominator and that is (3)(3)=9
81/9
=9

7 0

3 years ago

What is the direct linear variation equation for the relationship?

defon

$\bf \begin{array}{cccccclllll}
\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\
\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\
y&=&{{ K}}&\cdot&x
\\ \\
&& y={{ K }}x
\end{array}
\\ \quad \\

\begin{cases}
y=4\\
x=12
\end{cases}\implies y=Kx\implies 4=K\cdot 12$

solve for "K", to see what "K" is, or the "constant of variation",
once you found K, plug it back in y=Kx, and that's the equation

3 0

3 years ago

Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .