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3 years ago

Somebody pls help i’m confused

Chemistry

1 answer:

gavmur [86]3 years ago

7 0

I believe the answer is Zinc because it has 30protona

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For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coeffici

Brut [27]

Question:

For the cell constructed from the hydrogen electrode and metal-insoluble salt electrode, B) calculate the mean activity coefficient for 0.124 b HCl solution if E=0.342 V at 298 K

Answer:

The mean activity coefficient for HCl solution is 0.78.

Explanation:

Activity coefficient is defined as the ratio of any chemical activity of any substance with its molar concentration. So in an electrochemical cell, we can write activity coefficient as γ. The equation for determining the mean activity coefficient is

$E=E_{0}-0.0514 \mathrm{V} \ln \gamma$

As we know that $E_{0}$ = 0.22 V and E = 0.342 V, the equation will become

$0.342 V+0.0514 V \ln (0.124)=0.22 V-0.0514 V \ln \gamma$

$0.342 V-0.222 V=-0.0514 V(\ln \gamma+\ln 0.124)$

$0.12 \mathrm{V}=-0.0514 \mathrm{V}(\ln \gamma+\ln 0.124)$

$\frac{0.12}{0.0514}=-\ln (0.124 \gamma)$

$-2.3346=\ln (0.124 \gamma)$

$e^{-2.3346}=0.124 \gamma$

$0.0968=0.124 \gamma$

$\gamma=\frac{0.0968}{0.124}=0.78$

So, the mean activity coefficient is 0.78.

6 0

3 years ago

The change in the standard Gibbs free energy (ΔGº) for the dissociation of nitrous acid (HNO2) at 298 K is 19.09 kJ. If the pH o

Fynjy0 [20]

The change in the standard Gibbs free energy (ΔGº) for the dissociation of nitrous acid (HNO2) at 298 K is 19.09 kJ. If the pH of the solution after equilibrium is reached is 1.30 and the NO2 – concentration at equilibrium is 0.00060 M. What is the equilibrium concentration of HNO2? Hint: Use pH to determine the equilibrium concentration of H+ .
HNO2(aq) H + (aq) + NO2 – (aq)

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4 years ago

Consider the following three-step reaction pathway.

Alenkinab [10]

Answer:

$NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2$

Explanation:

The intermediates are the products of all the steps of the reaction pathway, with the exception of the last one. So the intermediates will be:

N2O2 from the first step
N2O from the second step

The list from reactant to final product:

$NO \longrightarrow N_2O_2 \longrightarrow N_2O \longrightarrow N2$

Note: the water is considered a by-product, given that is not the product of interest in this steps.

7 0

3 years ago

75.0 grams NaBr Find the molar mass and number of moles

AVprozaik [17]

Answer:

Molar mass = 103.0 g/mol,

0.728 mol NaBr

Explanation:

Molar mass M(NaBr) = M(Na) + M(Br) = 23.0 + 80.0 = 103.0 g/mol

75.0 g NaBr * 1 mol NaBr/103.0 g NaBr=0.728 mol NaBr

7 0

3 years ago

tankabanditka [31]

Watershed
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3 years ago