Answer:
FADH₂ → Q coenzyme → Complex III → c cytochrome → Complex IV → O₂
Explanation:
During oxidative phosphorylation, the electrons from NADH and FADH₂ are combined with O₂ and the energy released in the process is used to synthesize ATP from ADP.
The components of the electron transport chain are located in the internal part of the mitochondrial membrane in eukaryotic cells, and in the cell membrane in bacteria. The transporters in the electron transport chain are organized into four complexes in the inner mitochondrial membrane. A fifth complex then couples these reactions to the ATP synthesis.
Complex II receives the electrons from the succinate, which is an intermediary in the Krebs cycle. These electrons are transferred to the FADH₂ and then to the Q coenzyme. This liposoluble molecule will transport the electrons from Complex II to Complex III. In this complex, the electrons are transferred from the <em>b</em> cytochrome to the <em>c</em> cytochrome. This <em>c </em>cytochrome, which is a peripheric membrane protein located in the external part of the inner membrane, then transports the electrons to Complex IV where finally they are transferred to the oxygen.
Mg+Cl2--> MgCl2
Magnesium plus chlorine equals magnesium chloride
Answer: Rate in terms of disappearance of
= ![-\frac{1d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BNO%5D%7D%7B2dt%7D)
Rate in terms of disappearance of
= ![-\frac{1d[Cl_2]}{1dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BCl_2%5D%7D%7B1dt%7D)
Rate in terms of appearance of
= ![\frac{1d[NOCl]}{2dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1d%5BNOCl%5D%7D%7B2dt%7D)
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
Rate in terms of disappearance of = ![-\frac{1d[NO]}{2dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BNO%5D%7D%7B2dt%7D)
Rate in terms of disappearance of = ![-\frac{1d[Cl_2]}{1dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1d%5BCl_2%5D%7D%7B1dt%7D)
Rate in terms of appearance of
= ![+\frac{1d[NOCl]}{2dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1d%5BNOCl%5D%7D%7B2dt%7D)
Answer:
a) T
b) T
c) F
d) F
e) T
f) T
g) T
h) F
I) F
j) F
k) F
l) F
Explanation:
The w/v concentration is obtained from, mass/volume. Hence;
%w/v= 50/1000= 5%
In the %w/w we have;
25g/100 g = 25% w/w
In combustion reaction, energy is given out hence it is exothermic.
Neutralization reaction yields a salt and water
% by mass of carbon is obtained from;
8× 12/114 × 100 = 84.1%
All the ionic substances mentioned have very low solubility in water.
One mole of a substance contains the Avogadro's number of each atom in the compound.
There are two iron atoms so one mole contains 2× 55.85 g of iron.
Some sulphates such as BaSO4 are insoluble in water.
Halides are soluble in water hence NaI is soluble in water.
The equation does not balance with the given coefficients because the number of atoms of each element on both sides differ.
The equation represents a decomposition of calcium carbonate as written.
The best and most correct answer among the choices provided by the question is the second choice , b. sodium hydroxide .
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