Answer:
Q = 555200 J
Explanation:
∴ mass (m) = 80 kg
∴ c = 3470 J/Kg.K
∴ T1 = 37°C ≅ 310 K
∴ T2 = 39°C ≅ 312 K
⇒ ΔT = T2 - T1 = 312 K - 310 K = 2 K
⇒ Q = (80 Kg)*(3470 J/Kg.K)*(2 K)
⇒ Q = 555200 J ≅ 600000 J ≅ 6 E5 J
Balancing means there are equal amount of molecules on each side, both reactant and products. This is a method I like to do.
Under, I count how many molecules are in each side.
Cr2O3+Mg -->Cr + MgO
Cr: 2 1
O: 3 1
Mg: 1 1
Let's guess and make the number of oxygens equal on both sides.
Cr2O3+Mg -->Cr + 3MgO
Cr: 2 1
O: 3 3 EQUAL
Mg: 1 3
See what we did there? We multiplied the MgO on the products side by 3 so we can have 3 oxygens. Now let's multiply the Mg on the reactants by three so Mg AND O can be equal.
Cr2O3+3Mg -->Cr + 3 MgO
Cr: 2 1
O: 3 3 EQUAL
Mg: 3 3 EQUAL
Finally, we just need to multiply the loner Cr in the products side by two to make it equal for all elements.
Cr2O3+3Mg -->2Cr + 3 MgO
Answer:
it's 5.93% but that's not an option so 6%
Explanation:
Answer:
Explanation:
Chlorine is the element of group 17 and third period. The atomic number of chlorine is 17 and the symbol of the element is Cl.
The electronic configuration of the element chlorine is:-
Chloride ion is formed when chlorine atom gain one more electron. So, the ground-state electron configuration for the chloride ion is:-