Question

An archer shot a 0.06 kg arrow at a target. The arrow accelerated at 5,000 m/s/s to reach a speed of 50.0 m/s as it left the bow. During this ACCELERATION, what was the net force on the arrow to the nearest newton? *
1 point
A. 3 N
B. 833 N
C. 300 N
D. None of the above

Answer 1

Answer;

C. 300 N

Explanation;

From Newton second's Law of motion, the resultant force is directly proportional to the rate of change in momentum.

Therefore;

F = ma ; where F is the resultant force, m is the mass and a is the acceleration.

Therefore;

F = 0.06 kg × 5,000 m/s/s

  = 300 N