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4 years ago

Help me answer the question please I don’t get it this is earth science not chemistry.

Chemistry

1 answer:

andrew11 [14]4 years ago

3 0

See a similar question to this one answered here:

https://brainly.in/question/4914083

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What is likely to happen to the population of thrushes the population of voles decreases?

Andrei [34K]

Answer:

I think it will decrease

7 0

3 years ago

The process of burning a fossil fuel to release energy is called

Irina-Kira [14]

Answer:combustion

Explanation:

5 0

3 years ago

How many liters of carbon dioxide will be produced when 89.5 L of ethane are burned? (One mole of any gas occupies 22.4 L under

yan [13]

Answer:

179 L of CO2

Explanation:

Given the equation of the reaction;

C2H6(g) + 7/2 O2(g) -------> 2CO2(g) + 3H2O(g)

Now 1 mole of ethane yields 2 moles of CO2 from the balanced reaction equation

1 mole of a gas occupies 22.4 L volume so,

22.4 L of ethane yields 44.8 L of CO2

89.5 L of ethane yields 89.5 * 44.8/22.4 = 179 L of CO2

4 0

3 years ago

How many moles of Fe are produced from 7 moles of Zn? Zn(s) + FeSO4(aq) → ZnSO4(aq) + Fe(s)

guajiro [1.7K]

Answer:

7 mol Fe

General Formulas and Concepts:

Chemistry

Stoichiometry

Explanation:

Step 1: Define

RxN: Zn (s) + FeSO₄ (aq) → ZnSO₄ (aq) + Fe (s)

Given: 7 moles Zn

Step 2: Stoichiometry

$7 \ mol \ Zn(\frac{1 \ mol \ Fe}{1 \ mol \ Zn} )$ = 7 mol Fe

Step 3: Check

We are given 1 sig fig.

Since our final answer is in 1 sig fig, there is no need to round.

3 0

3 years ago

A sample of gas is held at 100oc at a volume of 20 L.if the volume is increased to 40 L what is the new temperature of the gas i

ElenaW [278]

Answer:

470 °C

Explanation:

This looks like a case where we can use Charles’ Law:

$\dfrac{V_{1}}{T_{1}} =\dfrac{V_{2}}{T_{2}}$

Data:

V₁ = 20 L; T₁ = 100 °C

V₂ = 40 L; T₂ = ?

Calculations:

(a) Convert the temperature to kelvins

T₁ = (100 + 273.15) K = 373.15 K

(b) Calculate the new temperature

$\begin{array}{rcl}\dfrac{V_{1}}{T_{1}}& =&\dfrac{V_{2}}{T_{2}}\\\\ \dfrac{\text{20 L}}{\text{373.15 K}} &=&\dfrac{\text{40 L}}{T_{2}}\\\\{\text{15 000 K}} & = & 20T_{2}\\T_{2} & = &\dfrac{\text{15 000 K}}{20 }\\\\T_{2} & = & \textbf{750 K}\\\end{array}$

Note: The answer can have only two significant figures because that is all you gave for the volumes.

(c) Convert the temperature to Celsius

T₂ = (750 – 273.15) °C = 470 °C

3 0

3 years ago