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mel-nik [20]
3 years ago
6

a 5.00 kg plane is speeding up on the ground with an applied force of 706 N. If the net force is 450 N, what would be the force

due to air resistance
Physics
1 answer:
loris [4]3 years ago
5 0

Answer:

The force due to air resistance is 256 N.

Explanation:

Given;

mass of the plane, m = 5 kg

applied force on the plane, Fa = 706 N

the net force on the plane, ∑F= 450 N

Let the force due to air resistance = Fr

The net force on the plane is given as;

Net force = applied force - force due to air resistance

∑F = Fa - Fr

Fr = Fa - ∑F

Fr = 706 - 450

Fr = 256 N.

Therefore, the force due to air resistance is 256 N.

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A circular test track for cars has a circumference of 3.5 kmkm . A car travels around the track from the southernmost point to t
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Answer:

(A) Distance will be equal to 1.75 km

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(a) It is given that car travels from southernmost point to the northernmost point.

For this car have to travel the distance equal to semi perimeter of the circular track

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(b) If car go along the diameter of the circular track then it will also go from southernmost point to the northernmost point. and it will be equal to diameter of the track

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3 years ago
How the energy is transformed
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6 0
3 years ago
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If you speed up from rest to 12m/s in 3 seconds, what is your acceleration?
boyakko [2]


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3 years ago
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To determine the height of a flagpole, Abby throws a ball straight up and times it. She sees that the ball goes by the top of th
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Answer:

H = 10.05 m

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