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marshall27 [118]
3 years ago
8

What is the domain and derivative of f(x)=ln(2xsqrt(2+x))?

Mathematics
1 answer:
wolverine [178]3 years ago
5 0
For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining 
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
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Can someone help me out plz ??!
scoray [572]

Answer:

≈ 62.8

Step-by-step explanation:

Using the equal ratios of

\frac{areaof circle}{areaofsector} = \frac{circleangle}{sectorangle}, that is

\frac{100\pi }{sector} = \frac{2\pi }{\frac{2\pi }{5} } = 5, thus

5 × sector = 100π ( divide both sides by 5 )

sector = 20π = 20 × 3.14 = 62.8 units²

7 0
3 years ago
To make ribbon and bow for a hat, Stacey needs 5/6 yard of black ribbon and 2/3 yard of red ribbon. how much total ribbon does s
larisa86 [58]
First make the denominators of the fractions the same by multiplying.

\frac{2}{3} × \frac{2}{2}
=\frac{4}{6}

Now we just need to add the fractions together

\frac{5}{6} +  \frac{4}{6}
= \frac{9}{6}

9/6 would be the answer, but it can be simplified further, then converted into decimal form.

\frac{9}{6} ÷ \frac{3}{3}
=\frac{3}{2}
=1.5 yards

Your final answer is 1.5 yards of ribbon are needed.
7 0
3 years ago
Read 2 more answers
In the box, type the number that will correctly complete the sentence.
Tpy6a [65]

Answer:

1

Step-by-step explanation:

One.  For example, if we chose 5 as the number, then the multiplicative inverse would be 1/5.  Multiplying 5 by 1/5 results in one (1).

7 0
3 years ago
Please help du tomorrow
Leokris [45]
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².

To find the perimeter of each, we add the area of all sides.  For the first figure, the missing sides are 1 cm and 6 cm.  To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.

For the second figure, the missing sides are 4 cm and 3 cm.  To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.

For the third figure, the missing sides are 3 cm, 3 cm and 8 cm.  To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.

For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm.  To find the area, we have two squares whose dimensions are 10x10.

For the fifth figure, the missing sides are 3 cm and 9 cm.  To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
3 0
3 years ago
Dx+hy=j,forx   x=    thanx for any and all help
Crazy boy [7]
dx+hy=j \\ \\ dx = j-hy \ \ / : \ d \\ \\d\neq 0\\ \\x=\frac{j-hy }{d}


6 0
3 years ago
Read 2 more answers
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