Answer:
Explanation:
Energy stored in a capacitor
= 1/2 C₁V²
capacity of a capacitor
c = εK A / d
k is dielectric and d is distance between plates .
When the distance between the plates is halved and then filled with a dielectric (κ = 4.3)
capacity becomes 4.3 x 2 times
New capacity
C₂ = 8.6 C₁
Energy of modified capacitor
1/2 C₂ V²= 1/2 x 8.6 c x V²
Energy becomes
8.6 times.
Energy stored = 8.6 x 10⁻⁴ J
Answer:
(7.8) x (9.8 m/s) = 76.44 m/s
during the time he spent falling.
Since his falling speed was zero when he 'stepped' off of the top,
he hit the ground at 76.44 m/s.
That's about 170 miles per hour.
I'll bet he left one serious crater!
I hope this helps too! :D
Explanation:
The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.
<u>Given the following data:</u>
Charge = C.
Distance = 0.100 m.
<u>Scientific data:</u>
Coulomb's constant =
<h3>How to calculate the net force.</h3>
In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = F₁₃ + F₂₃
Mathematically, the electrostatic force between two (2) charges is given by this formula:
<u>Where:</u>
- r is the distance between two charges.
<u>Note:</u> d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.
For electrostatic force (F₁₃);
F₁₃ = 1.24 Newton.
For electrostatic force (F₂₃);
F₂₃ = 4.96 Newton.
Therefore, the magnitude of the net force that is acting on particle q₃ is given by:
F₃ = 1.24 + 4.96
F₃ = 6.2 Newton.
Read more on charges here: brainly.com/question/14372859
<u>True</u> is your answer.
Hope this helps....